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Use synthetic division and the Remainder Theorem to find the indicated function value.

[tex]\[
\begin{array}{l}
f(x) = 3x^3 - 5x^2 - 8x + 5; \\
f(-4) = \square
\end{array}
\][/tex]


Sagot :

Certainly! Let's use synthetic division and the Remainder Theorem to find the value of [tex]\( f(-4) \)[/tex] for the polynomial [tex]\( f(x) = 3x^3 - 5x^2 - 8x + 5 \)[/tex].

Here are the steps:

1. Set up synthetic division: Write down the coefficients of the polynomial and the value you want to evaluate—in this case, [tex]\(-4\)[/tex].

Coefficients: [tex]\(3, -5, -8, 5\)[/tex]

Value to evaluate: [tex]\(-4\)[/tex]

2. Write the coefficients and the value you're evaluating to the left:

```
-4 | 3 | -5 | -8 | 5
```

3. Bring down the [tex]\(3\)[/tex] to start:

```
-4 | 3 | -5 | -8 | 5
└── 3
```

4. Multiply and add: Multiply the value you are evaluating (-4) by the number you just brought down (3), then add this result to the next coefficient (-5):

- Multiply: [tex]\(-4 \times 3 = -12\)[/tex]
- Add: [tex]\(-5 + (-12) = -17\)[/tex]

```
-4 | 3 | -5 | -8 | 5
└── 3 -17
```

5. Repeat the process: Multiply the value you are evaluating (-4) by the result you just obtained (-17) and then add to the next coefficient (-8):

- Multiply: [tex]\(-4 \times (-17) = 68\)[/tex]
- Add: [tex]\(-8 + 68 = 60\)[/tex]

```
-4 | 3 | -5 | -8 | 5
└── 3 -17 60
```

6. One last time: Multiply the value you are evaluating (-4) by the result you just obtained (60) and then add to the final coefficient (5):

- Multiply: [tex]\(-4 \times 60 = -240\)[/tex]
- Add: [tex]\(5 + (-240) = -235\)[/tex]

```
-4 | 3 | -5 | -8 | 5
└── 3 -17 60 -235
```

7. Interpret the result:

The last value on the row is the value of the polynomial at [tex]\( x = -4 \)[/tex]. Therefore, [tex]\( f(-4) = -235 \)[/tex].

So by using synthetic division and the Remainder Theorem, we find that [tex]\( f(-4) = -235 \)[/tex].