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Label each solution as concentrated (C) or dilute (D) based on the table.

A [tex]$\square$[/tex]
B [tex]$\square$[/tex]
C [tex]$\square$[/tex]
D [tex]$\square$[/tex]
E [tex]$\square$[/tex]
F [tex]$\square$[/tex]

\begin{tabular}{|l|l|c|}
\hline
\begin{tabular}{l}
Acid/Base
\end{tabular} & Molarity & \begin{tabular}{l}
Concentrated (C) \\
Dilute (D)
\end{tabular} \\
\hline
\multirow{2}{}{HCl} & 12 M & A \\
\hline
& 0.5 M & B \\
\hline
\multirow{2}{}{NaOH} & 0.01 M & C \\
\hline
& 6.0 M & D \\
\hline
\multirow{2}{*}{[tex]$H_2SO_4$[/tex]} & 0.05 M & E \\
\cline{2-3}
& 10 M & F \\
\hline
\end{tabular}

Sagot :

GinnyAnsweridn
Alright! Let's go through the process of labeling each compound as either concentrated (C) or dilute (D) based on their given molarities.

Here's the data again for clarity:
- HCl
- 12 M (Label A)
- 0.5 M (Label B)
- NaOH
- 0.01 M (Label C)
- 6.0 M (Label D)
- H₂SO₄
- 0.05 M (Label E)
- 10 M (Label F)

The rule we're using to determine if a solution is "Concentrated" (C) or "Dilute" (D) is as follows:
- A solution is labeled Concentrated (C) if its molarity is 1.0 M or higher.
- A solution is labeled Dilute (D) if its molarity is less than 1.0 M.

Let's apply this rule to each compound:

1. HCl with a molarity of 12 M (Label A):
- 12 M is greater than 1.0 M, so it is Concentrated (C).

2. HCl with a molarity of 0.5 M (Label B):
- 0.5 M is less than 1.0 M, so it is Dilute (D).

3. NaOH with a molarity of 0.01 M (Label C):
- 0.01 M is less than 1.0 M, so it is Dilute (D).

4. NaOH with a molarity of 6.0 M (Label D):
- 6.0 M is greater than 1.0 M, so it is Concentrated (C).

5. H₂SO₄ with a molarity of 0.05 M (Label E):
- 0.05 M is less than 1.0 M, so it is Dilute (D).

6. H₂SO₄ with a molarity of 10 M (Label F):
- 10 M is greater than 1.0 M, so it is Concentrated (C).

So, the labels for each compound are as follows:

- Label A: C
- Label B: D
- Label C: D
- Label D: C
- Label E: D
- Label F: C

Therefore, the correct labeling is:
```
('C', 'D', 'D', 'C', 'D', 'C')
```

You can fill in the table accordingly:
- A: C
- B: D
- C: D
- D: C
- E: D
- F: C
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