Get expert advice and insights on any topic with IDNLearn.com. Ask any question and receive accurate, in-depth responses from our dedicated team of experts.
Sagot :
Sure, let's start by translating the ages into algebraic expressions based on the information provided:
1. Carl's age: Let [tex]\( x \)[/tex] be Caitlyn's age. Since Carl is 2 years older than Caitlyn, Carl's age is [tex]\( x + 2 \)[/tex].
2. Daryl's age: Since Daryl is 5 years older than Carl, Daryl’s age is [tex]\( (x + 2) + 5 = x + 7 \)[/tex].
The next step involves setting up the inequality based on the product of Carl and Daryl's ages, which needs to be at least 160:
[tex]\[ (x + 2)(x + 7) \geq 160 \][/tex]
Now, let's expand this product:
1. First, distribute [tex]\( x + 2 \)[/tex] and [tex]\( x + 7 \)[/tex]:
[tex]\[ (x + 2)(x + 7) = x^2 + 7x + 2x + 14 \][/tex]
2. Combine like terms:
[tex]\[ x^2 + 7x + 2x + 14 = x^2 + 9x + 14 \][/tex]
So, the inequality simplifies to:
[tex]\[ x^2 + 9x + 14 \geq 160 \][/tex]
The correct inequality that represents this situation is:
[tex]\[ x^2 + 9x + 14 \geq 160 \][/tex]
Thus, the correct answer is:
[tex]\[ \boxed{x^2 + 9x + 14 \geq 160} \][/tex]
1. Carl's age: Let [tex]\( x \)[/tex] be Caitlyn's age. Since Carl is 2 years older than Caitlyn, Carl's age is [tex]\( x + 2 \)[/tex].
2. Daryl's age: Since Daryl is 5 years older than Carl, Daryl’s age is [tex]\( (x + 2) + 5 = x + 7 \)[/tex].
The next step involves setting up the inequality based on the product of Carl and Daryl's ages, which needs to be at least 160:
[tex]\[ (x + 2)(x + 7) \geq 160 \][/tex]
Now, let's expand this product:
1. First, distribute [tex]\( x + 2 \)[/tex] and [tex]\( x + 7 \)[/tex]:
[tex]\[ (x + 2)(x + 7) = x^2 + 7x + 2x + 14 \][/tex]
2. Combine like terms:
[tex]\[ x^2 + 7x + 2x + 14 = x^2 + 9x + 14 \][/tex]
So, the inequality simplifies to:
[tex]\[ x^2 + 9x + 14 \geq 160 \][/tex]
The correct inequality that represents this situation is:
[tex]\[ x^2 + 9x + 14 \geq 160 \][/tex]
Thus, the correct answer is:
[tex]\[ \boxed{x^2 + 9x + 14 \geq 160} \][/tex]
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Your questions deserve reliable answers. Thanks for visiting IDNLearn.com, and see you again soon for more helpful information.