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Which pair shares the same empirical formula?

A. [tex]C_2H_4[/tex] and [tex]C_6H_6[/tex]
B. [tex]CH_2[/tex] and [tex]CH_4[/tex]
C. [tex]CH_3[/tex] and [tex]C_2H_6[/tex]
D. [tex]CH[/tex] and [tex]C_2H_4[/tex]

Sagot :

GinnyAnsweridn
To determine which pair of compounds share the same empirical formula, we must first understand what an empirical formula is. An empirical formula represents the simplest whole-number ratio of atoms in a compound.

Let's analyze each pair of compounds and simplify their formulas step by step.

1. Pair: [tex]\(C_2H_4\)[/tex] and [tex]\(C_6H_6\)[/tex]

- For [tex]\(C_2H_4\)[/tex]:
- Carbon atoms: 2
- Hydrogen atoms: 4
- The ratio is [tex]\(2:4\)[/tex], which simplifies to [tex]\(1:2\)[/tex]. The empirical formula is [tex]\(CH_2\)[/tex].

- For [tex]\(C_6H_6\)[/tex]:
- Carbon atoms: 6
- Hydrogen atoms: 6
- The ratio is [tex]\(6:6\)[/tex], which simplifies to [tex]\(1:1\)[/tex]. The empirical formula is [tex]\(CH\)[/tex].

These do not share the same empirical formula.

2. Pair: [tex]\(CH_2\)[/tex] and [tex]\(CH_4\)[/tex]

- For [tex]\(CH_2\)[/tex]:
- Carbon atoms: 1
- Hydrogen atoms: 2
- The ratio is already [tex]\(1:2\)[/tex]. The empirical formula remains [tex]\(CH_2\)[/tex].

- For [tex]\(CH_4\)[/tex]:
- Carbon atoms: 1
- Hydrogen atoms: 4
- The ratio is already [tex]\(1:4\)[/tex]. The empirical formula remains [tex]\(CH_4\)[/tex].

These do not share the same empirical formula.

3. Pair: [tex]\(CH_3\)[/tex] and [tex]\(C_2H_6\)[/tex]

- For [tex]\(CH_3\)[/tex]:
- Carbon atoms: 1
- Hydrogen atoms: 3
- The ratio is already [tex]\(1:3\)[/tex]. The empirical formula remains [tex]\(CH_3\)[/tex].

- For [tex]\(C_2H_6\)[/tex]:
- Carbon atoms: 2
- Hydrogen atoms: 6
- The ratio is [tex]\(2:6\)[/tex], which simplifies to [tex]\(1:3\)[/tex]. The empirical formula is [tex]\(CH_3\)[/tex].

These do share the same empirical formula.

4. Pair: [tex]\(CH\)[/tex] and [tex]\(C_2H_4\)[/tex]

- For [tex]\(CH\)[/tex]:
- Carbon atoms: 1
- Hydrogen atoms: 1
- The ratio is already [tex]\(1:1\)[/tex]. The empirical formula remains [tex]\(CH\)[/tex].

- For [tex]\(C_2H_4\)[/tex]:
- Carbon atoms: 2
- Hydrogen atoms: 4
- The ratio is [tex]\(2:4\)[/tex], which simplifies to [tex]\(1:2\)[/tex]. The empirical formula is [tex]\(CH_2\)[/tex].

These do not share the same empirical formula.

After comparing all pairs, we find that the third pair, [tex]\(CH_3\)[/tex] and [tex]\(C_2H_6\)[/tex], shares the same empirical formula [tex]\(CH_3\)[/tex].

Thus, the pair that shares the same empirical formula is:
[tex]\[ \boxed{3} \][/tex]
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