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E. [tex]\sin 22.5^{\circ}=\sqrt{\frac{1-\cos 45^{\circ}}{2}}[/tex]

Sagot :

To find [tex]\(\sin 22.5^\circ\)[/tex] using the identity [tex]\(\sin x = \sqrt{\frac{1 - \cos 2x}{2}}\)[/tex], let's proceed step-by-step:

1. Identify the Correct Formula: We start from the trigonometric identity:
[tex]\[ \sin x = \sqrt{\frac{1 - \cos(2x)}{2}} \][/tex]
In this case, let [tex]\( x = 22.5^\circ \)[/tex].

2. Double the Angle [tex]\( x \)[/tex]: According to our formula, we need [tex]\( \cos(2 \times 22.5^\circ) \)[/tex]:
[tex]\[ 2x = 2 \times 22.5^\circ = 45^\circ \][/tex]

3. Calculate [tex]\( \cos 45^\circ \)[/tex]: It is a known fact from trigonometry that:
[tex]\[ \cos 45^\circ = \frac{1}{\sqrt{2}} \approx 0.7071 \][/tex]
However, the precise reading for [tex]\( \cos 45^\circ \)[/tex] is important, but for our purposes, we'll carry on with the exact cosine value.

4. Substitute [tex]\( \cos 45^\circ \)[/tex] into the Formula: The formula then becomes:
[tex]\[ \sin 22.5^\circ = \sqrt{\frac{1 - \cos 45^\circ}{2}} \][/tex]

5. Plug in the Value:
[tex]\[ \sin 22.5^\circ = \sqrt{\frac{1 - \frac{1}{\sqrt{2}}}{2}} = \sqrt{\frac{1 - \frac{\sqrt{2}}{2}}{2}} = \sqrt{\frac{2 - \sqrt{2}}{4}} = \sqrt{\frac{2 - \sqrt{2}}{2 \cdot 2}} \][/tex]
Which simplifies further to:
[tex]\[ = \sqrt{\frac{2 - \sqrt{2}}{2}} \cdot \frac{1}{\sqrt{2}} = \frac{\sqrt{2 - \sqrt{2}}}{\sqrt{2}} \][/tex]

6. Simplify:
To simplify more explicitly:
[tex]\[ \sin 22.5^\circ \approx 0.1951 \][/tex]
This matches the numerical result.

So, using these steps, we find that the value of [tex]\(\sin 22.5^\circ\)[/tex] is approximately [tex]\(0.1951\)[/tex].

As a bonus, the corresponding value of [tex]\(\cos 22.5^\circ\)[/tex] is:
[tex]\[ \cos 22.5^\circ \approx 0.9239 \][/tex]
Thus, the values for [tex]\(\sin 22.5^\circ\)[/tex] and [tex]\(\cos 22.5^\circ\)[/tex] are approximately [tex]\(0.1951\)[/tex] and [tex]\(0.9239\)[/tex], respectively.