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Find the standard form of the equation of the hyperbole withe the given characteristics
Verteces (1,-2),(1,-6); passes through the points (5,-10)


Sagot :

To find the standard form of the equation of the hyperbola with the given vertices and a point it passes through, we need to follow these steps:

1.  Determine the center of the hyperbola:

  The vertices of the hyperbola are [tex]\((1, -2)\) and \((1, -6)\).[/tex]

  The center [tex]\((h, k)\)[/tex] is the midpoint of the vertices. So,

[tex]\[ h = \frac{1 + 1}{2} = 1 \] \[ k = \frac{-2 + (-6)}{2} = \frac{-8}{2} = -4 \][/tex]

  Thus, the center of the hyperbola is [tex]\((1, -4)\).[/tex]

2. Determine the distance between the vertices:

  The distance between the vertices is [tex]\(2a\)[/tex]  (where [tex]\(a\)[/tex] is the distance from the center to each vertex).

 [tex]\[ 2a = |-2 - (-6)| = |-2 + 6| = |4| = 4 \implies a = 2 \][/tex]

3. Determine the orientation of the hyperbola:

  Since the vertices have the same x-coordinate and different y-coordinates, the hyperbola opens vertically.

  The standard form of the equation for a vertically oriented hyperbola is:

[tex]\[ \frac{(y - k)^2}{a^2} - \frac{(x - h)^2}{b^2} = 1 \][/tex]

  Substituting [tex]\(h = 1\), \(k = -4\), and \(a = 2\),[/tex]  we get:

[tex]\[ \frac{(y + 4)^2}{4} - \frac{(x - 1)^2}{b^2} = 1 \][/tex]

4. Determine [tex]\(b^2\)[/tex] using the given point:

  The hyperbola passes through the point [tex]\((5, -10)\).[/tex]

  Substitute [tex]\((x, y) = (5, -10)\)[/tex] into the equation:

[tex]\[ \frac{(-10 + 4)^2}{4} - \frac{(5 - 1)^2}{b^2} = 1 \] \[ \frac{(-6)^2}{4} - \frac{(4)^2}{b^2} = 1 \] \[ \frac{36}{4} - \frac{16}{b^2} = 1 \] \[ 9 - \frac{16}{b^2} = 1 \] \[ 8 = \frac{16}{b^2} \] \[ b^2 = \frac{16}{8} = 2 \][/tex]

5. Write the standard form of the equation:

  Substitute [tex]\(a^2 = 4\) and \(b^2 = 2\)[/tex] into the standard form equation:

 [tex]\[ \frac{(y + 4)^2}{4} - \frac{(x - 1)^2}{2} = 1 \][/tex]

Thus, the standard form of the equation of the hyperbola is:

[tex]\[\boxed{\frac{(y + 4)^2}{4} - \frac{(x - 1)^2}{2} = 1}\][/tex]