Answered

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What will be the output of the following code?

```cpp
#include
using namespace std;

int main() {
int n;
for (n = 5; n > 0; n--) {
if (n == 3)
break;
}
return 0;
}
```

(Note: The code provided seems to have a syntax error. Here is the corrected version.)

Sagot :

GinnyAnsweridn
Let’s walk through the step-by-step execution of the provided C++ code to determine its output:

1. Initialization:
- An integer `n` is declared.

2. For Loop:
- The for loop initializes `n` to 5.
- The loop will execute as long as `n` is greater than 0.
- After each iteration, `n` will be decremented by 1.

3. First Iteration (n = 5):
- `n` is 5.
- The condition `if (n==3)` is checked, but `n` is not 3, so the loop continues.

4. Second Iteration (n = 4):
- `n` is 4.
- The condition `if (n==3)` is checked, but `n` is still not 3, so the loop continues.

5. Third Iteration (n = 3):
- `n` is 3.
- The condition `if (n==3)` is checked, and `n` equals 3 this time.
- As the condition is true, the `break` statement is executed, which causes an immediate exit from the loop.

6. Loop Exit:
- The loop exits when `n` reaches 3 due to the `break` statement.

Given this step-by-step explanation, the output will be the value of `n` when the loop is exited, which is `3`.

Therefore, the output of the code is:
```
3
```
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