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There are a total of 32 legs in a park with dogs and their owners.if the number of dogs is one less than the humans, how many humans are there

Sagot :

Zarahaider4211idn

Answer:

6 humans

Step-by-step explanation:

Solving the Problem

Understanding the Word Problem

We're told that a park has dogs and humans, and the total number of legs in the park is 32. Since each human and dogs have 2 and 4 legs each, respectively, an equation can be written to simulate this.

                                            2h + 4d = 32

where h represent humans and d for dogs.

The problem also tells us that the number of dogs is one less than the number of humans, saying if there were 9 humans, the number of dogs would be 8.

We can simulate this as

                                                d = h - 1.

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Solving for h (System of Equations)

We're told to find the number of humans in the park, meaning that we need to find the value of h using these two equations.

To solve this system, we can either use substitution or elimination, since the second equation is d written in terms of h, we use the first method.

                                             2h + 4(h - 1) = 32

                                             2h + 4h - 4 = 32

                                                 6h - 4 = 32

                                                    6h = 36

                                                       h = 6

So, there are 6 humans in the park.

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