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Sagot :
To solve the equation [tex]$\sqrt{5x - 3} = \sqrt{2x + 3}$[/tex], follow these steps:
1. Square both sides:
To eliminate the square roots, we square both sides of the equation:
[tex]\[ \left(\sqrt{5x - 3}\right)^2 = \left(\sqrt{2x + 3}\right)^2 \][/tex]
Simplifying the squares, we get:
[tex]\[ 5x - 3 = 2x + 3 \][/tex]
2. Isolate the variable [tex]\(x\)[/tex]:
To isolate [tex]\(x\)[/tex], we need to get all terms involving [tex]\(x\)[/tex] on one side and the constant terms on the other side. Begin by subtracting [tex]\(2x\)[/tex] from both sides:
[tex]\[ 5x - 2x - 3 = 3 \][/tex]
Simplify the left side:
[tex]\[ 3x - 3 = 3 \][/tex]
Next, add 3 to both sides to isolate the [tex]\(x\)[/tex] term:
[tex]\[ 3x - 3 + 3 = 3 + 3 \][/tex]
Simplify:
[tex]\[ 3x = 6 \][/tex]
3. Solve for [tex]\(x\)[/tex]:
Divide both sides by 3:
[tex]\[ x = \frac{6}{3} \][/tex]
Simplify the division:
[tex]\[ x = 2 \][/tex]
So, the solution to the equation [tex]\(\sqrt{5x - 3} = \sqrt{2x + 3}\)[/tex] is [tex]\(x = 2\)[/tex].
1. Square both sides:
To eliminate the square roots, we square both sides of the equation:
[tex]\[ \left(\sqrt{5x - 3}\right)^2 = \left(\sqrt{2x + 3}\right)^2 \][/tex]
Simplifying the squares, we get:
[tex]\[ 5x - 3 = 2x + 3 \][/tex]
2. Isolate the variable [tex]\(x\)[/tex]:
To isolate [tex]\(x\)[/tex], we need to get all terms involving [tex]\(x\)[/tex] on one side and the constant terms on the other side. Begin by subtracting [tex]\(2x\)[/tex] from both sides:
[tex]\[ 5x - 2x - 3 = 3 \][/tex]
Simplify the left side:
[tex]\[ 3x - 3 = 3 \][/tex]
Next, add 3 to both sides to isolate the [tex]\(x\)[/tex] term:
[tex]\[ 3x - 3 + 3 = 3 + 3 \][/tex]
Simplify:
[tex]\[ 3x = 6 \][/tex]
3. Solve for [tex]\(x\)[/tex]:
Divide both sides by 3:
[tex]\[ x = \frac{6}{3} \][/tex]
Simplify the division:
[tex]\[ x = 2 \][/tex]
So, the solution to the equation [tex]\(\sqrt{5x - 3} = \sqrt{2x + 3}\)[/tex] is [tex]\(x = 2\)[/tex].
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