Answered

Join IDNLearn.com and start exploring the answers to your most pressing questions. Discover the reliable solutions you need with help from our comprehensive and accurate Q&A platform.

How many moles of PbS are equivalent to 458 g of PbS?

Molar mass of PbS = 239.27 g/mol

[?] mol PbS

Sagot :

GinnyAnsweridn
To determine how many moles of PbS (Lead(II) sulfide) are equivalent to a given mass of 458 grams, we must use the following relationship between mass, molar mass, and moles:

[tex]\[ \text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} \][/tex]

Given data:
- Mass of PbS: 458 grams
- Molar mass of PbS: 239.27 grams per mole

Here's the step-by-step process:

1. Write down the formula:
[tex]\[ \text{Moles of PbS} = \frac{\text{Mass of PbS}}{\text{Molar Mass of PbS}} \][/tex]

2. Substitute the given values into the formula:
[tex]\[ \text{Moles of PbS} = \frac{458 \text{ grams}}{239.27 \text{ grams per mole}} \][/tex]

3. Perform the division:
[tex]\[ \text{Moles of PbS} = 1.9141555564843062 \text{ moles} \][/tex]

Therefore, the number of moles of PbS equivalent to 458 grams is approximately [tex]\( 1.9142 \)[/tex] moles, when rounded to four decimal places.
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.