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Which compounds have the empirical formula [tex]CH_2O[/tex]?

A. [tex]C_2H_4O_2[/tex]
B. [tex]C_3H_6O_3[/tex]
C. [tex]CH_2O_2[/tex]
D. [tex]C_5H_{10}O_5[/tex]
E. [tex]C_6H_{12}O_6[/tex]

Sagot :

GinnyAnsweridn
To determine which compounds have the empirical formula [tex]\( CH_2O \)[/tex], we need to simplify the molecular formulas given to see if they match [tex]\( CH_2O \)[/tex].

### Steps to Check Each Compound:

1. For [tex]\( C_2H_4O_2 \)[/tex]:
- Given: [tex]\( C = 2 \)[/tex], [tex]\( H = 4 \)[/tex], [tex]\( O = 2 \)[/tex]
- Simplify the ratio of the elements:
- Carbon: [tex]\( 2 / 2 = 1 \)[/tex]
- Hydrogen: [tex]\( 4 / 2 = 2 \)[/tex]
- Oxygen: [tex]\( 2 / 2 = 1 \)[/tex]
- Resulting formula: [tex]\( CH_2O \)[/tex]
- Conclusion: Yes, it matches [tex]\( CH_2O \)[/tex].

2. For [tex]\( C_3H_6O_3 \)[/tex]:
- Given: [tex]\( C = 3 \)[/tex], [tex]\( H = 6 \)[/tex], [tex]\( O = 3 \)[/tex]
- Simplify the ratio of the elements:
- Carbon: [tex]\( 3 / 3 = 1 \)[/tex]
- Hydrogen: [tex]\( 6 / 3 = 2 \)[/tex]
- Oxygen: [tex]\( 3 / 3 = 1 \)[/tex]
- Resulting formula: [tex]\( CH_2O \)[/tex]
- Conclusion: Yes, it matches [tex]\( CH_2O \)[/tex].

3. For [tex]\( CH_2O_2 \)[/tex]:
- Given: [tex]\( C = 1 \)[/tex], [tex]\( H = 2 \)[/tex], [tex]\( O = 2 \)[/tex]
- Simplify the ratio of the elements:
- Carbon: [tex]\( 1 / 1 = 1 \)[/tex]
- Hydrogen: [tex]\( 2 / 1 = 2 \)[/tex]
- Oxygen: [tex]\( 2 / 1 = 2 \)[/tex]
- Resulting formula: [tex]\( CH_2O_2 \)[/tex]
- Conclusion: No, it does not match [tex]\( CH_2O \)[/tex].

4. For [tex]\( C_5H_{10}O_5 \)[/tex]:
- Given: [tex]\( C = 5 \)[/tex], [tex]\( H = 10 \)[/tex], [tex]\( O = 5 \)[/tex]
- Simplify the ratio of the elements:
- Carbon: [tex]\( 5 / 5 = 1 \)[/tex]
- Hydrogen: [tex]\( 10 / 5 = 2 \)[/tex]
- Oxygen: [tex]\( 5 / 5 = 1 \)[/tex]
- Resulting formula: [tex]\( CH_2O \)[/tex]
- Conclusion: Yes, it matches [tex]\( CH_2O \)[/tex].

5. For [tex]\( C_6H_{12}O_6 \)[/tex]:
- Given: [tex]\( C = 6 \)[/tex], [tex]\( H = 12 \)[/tex], [tex]\( O = 6 \)[/tex]
- Simplify the ratio of the elements:
- Carbon: [tex]\( 6 / 6 = 1 \)[/tex]
- Hydrogen: [tex]\( 12 / 6 = 2 \)[/tex]
- Oxygen: [tex]\( 6 / 6 = 1 \)[/tex]
- Resulting formula: [tex]\( CH_2O \)[/tex]
- Conclusion: Yes, it matches [tex]\( CH_2O \)[/tex].

### Final List of Compounds Matching the Empirical Formula [tex]\( CH_2O \)[/tex]:

- [tex]\( C_2H_4O_2 \)[/tex]
- [tex]\( C_3H_6O_3 \)[/tex]
- [tex]\( C_5H_{10}O_5 \)[/tex]
- [tex]\( C_6H_{12}O_6 \)[/tex]

So, the correct answers are:

- [tex]\( C_2H_4O_2 \)[/tex]
- [tex]\( C_3H_6O_3 \)[/tex]
- [tex]\( C_5H_{10}O_5 \)[/tex]
- [tex]\( C_6H_{12}O_6 \)[/tex]
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