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What is the equation of the directrix of the parabola given by the equation [tex](y-3)^2=8(x-5)[/tex]?

A. [tex]y=3[/tex]
B. [tex]x=3[/tex]
C. [tex]x=5[/tex]
D. [tex]y=5[/tex]


Sagot :

To determine the equation of the directrix for the given parabola [tex]\((y - 3)^2 = 8(x - 5)\)[/tex], we will follow these steps:

1. Identify the standard form:
The equation [tex]\((y - 3)^2 = 8(x - 5)\)[/tex] is in the form [tex]\((y - k)^2 = 4p(x - h)\)[/tex], where [tex]\((h, k)\)[/tex] is the vertex of the parabola and [tex]\(p\)[/tex] is the distance from the vertex to the focus (and also from the vertex to the directrix).

2. Determine the parameters:
From the equation [tex]\((y - 3)^2 = 8(x - 5)\)[/tex], we compare it to the standard form [tex]\((y - k)^2 = 4p(x - h)\)[/tex]:
- [tex]\(h = 5\)[/tex]
- [tex]\(k = 3\)[/tex]
- [tex]\(4p = 8\)[/tex], which gives [tex]\(p = 2\)[/tex]

3. Find the directrix:
For a parabola in the form [tex]\((y - k)^2 = 4p(x - h)\)[/tex], the directrix is given by the line [tex]\(x = h - p\)[/tex]:
- Here, [tex]\(h = 5\)[/tex] and [tex]\(p = 2\)[/tex]
- Thus, the directrix is [tex]\(x = 5 - 2\)[/tex]

4. Calculate the directrix equation:
- [tex]\(x = 3\)[/tex]

Therefore, the equation of the directrix is [tex]\(\boxed{x = 3}\)[/tex].

Thus, the correct answer is B. [tex]\( x = 3 \)[/tex].