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Sagot :
To determine the car's acceleration, we can use the following formula for acceleration:
[tex]\[ a = \frac{v - u}{t} \][/tex]
where:
- [tex]\( u \)[/tex] is the initial velocity,
- [tex]\( v \)[/tex] is the final velocity, and
- [tex]\( t \)[/tex] is the time taken.
Given the values:
- Initial velocity, [tex]\( u = 10 \, \text{m/s} \)[/tex]
- Final velocity, [tex]\( v = 40 \, \text{m/s} \)[/tex]
- Time taken, [tex]\( t = 15 \, \text{seconds} \)[/tex]
We can plug these values into the formula:
[tex]\[ a = \frac{40 \, \text{m/s} - 10 \, \text{m/s}}{15 \, \text{seconds}} \][/tex]
This simplifies to:
[tex]\[ a = \frac{30 \, \text{m/s}}{15 \, \text{seconds}} \][/tex]
[tex]\[ a = 2 \, \text{m/s}^2 \][/tex]
Thus, the car's acceleration is [tex]\( 2 \, \text{m/s}^2 \)[/tex].
The correct answer is:
[tex]\[ 2 \, \text{m/s}^2 \][/tex]
[tex]\[ a = \frac{v - u}{t} \][/tex]
where:
- [tex]\( u \)[/tex] is the initial velocity,
- [tex]\( v \)[/tex] is the final velocity, and
- [tex]\( t \)[/tex] is the time taken.
Given the values:
- Initial velocity, [tex]\( u = 10 \, \text{m/s} \)[/tex]
- Final velocity, [tex]\( v = 40 \, \text{m/s} \)[/tex]
- Time taken, [tex]\( t = 15 \, \text{seconds} \)[/tex]
We can plug these values into the formula:
[tex]\[ a = \frac{40 \, \text{m/s} - 10 \, \text{m/s}}{15 \, \text{seconds}} \][/tex]
This simplifies to:
[tex]\[ a = \frac{30 \, \text{m/s}}{15 \, \text{seconds}} \][/tex]
[tex]\[ a = 2 \, \text{m/s}^2 \][/tex]
Thus, the car's acceleration is [tex]\( 2 \, \text{m/s}^2 \)[/tex].
The correct answer is:
[tex]\[ 2 \, \text{m/s}^2 \][/tex]
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