Sure, let's break down the solution step-by-step:
1. Given Information:
- We have [tex]\( 11.7 \)[/tex] grams of NaCl dissolved in [tex]\( 500 \, \text{cm}^3 \)[/tex] of solution.
- We also know that tetrachloromethane has a calculated mass given by [tex]\( 2440^2 \times 13 \)[/tex] and it is dissolved to make a [tex]\( 100 \, \text{cm}^3 \)[/tex] solution.
2. Determine the mass of tetrachloromethane:
- From the given information, the mass of the tetrachloromethane is:
[tex]\[
2440^2 \times 13 = 5,953,600 \times 13 = 77,396,800 \, \text{grams}
\][/tex]
- Therefore, the mass of tetrachloromethane is [tex]\( 77,396,800 \)[/tex] grams.
3. Summarize the given values:
- The relevant quantities we have are:
- [tex]\( 11.7 \)[/tex] grams of NaCl
- [tex]\( 500 \, \text{cm}^3 \)[/tex] of NaCl solution
- [tex]\( 77,396,800 \)[/tex] grams of tetrachloromethane
- [tex]\( 100 \, \text{cm}^3 \)[/tex] of tetrachloromethane solution
4. Final Answer:
- The values provided are [tex]\( 11.7 \)[/tex] grams of NaCl, [tex]\( 500 \, \text{cm}^3 \)[/tex] of NaCl solution, [tex]\( 77,396,800 \)[/tex] grams of tetrachloromethane mass, and [tex]\( 100 \, \text{cm}^3 \)[/tex] of tetrachloromethane solution.
This concludes our detailed breakdown of the solution.
