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Sagot :
To find [tex]\( f(-2) \)[/tex] for the function [tex]\( f(x) = -3x + 3 \)[/tex], follow these steps:
1. Substitute [tex]\( x = -2 \)[/tex] into the function [tex]\( f(x) \)[/tex].
2. The function [tex]\( f(x) \)[/tex] is given by:
[tex]\[ f(x) = -3x + 3 \][/tex]
3. Substitute [tex]\( x = -2 \)[/tex] into the function:
[tex]\[ f(-2) = -3(-2) + 3 \][/tex]
4. Multiply inside the function:
[tex]\[ -3(-2) = 6 \][/tex]
5. Add the remaining constant term:
[tex]\[ 6 + 3 = 9 \][/tex]
Hence, the value of [tex]\( f(-2) \)[/tex] is:
[tex]\[ f(-2) = 9 \][/tex]
1. Substitute [tex]\( x = -2 \)[/tex] into the function [tex]\( f(x) \)[/tex].
2. The function [tex]\( f(x) \)[/tex] is given by:
[tex]\[ f(x) = -3x + 3 \][/tex]
3. Substitute [tex]\( x = -2 \)[/tex] into the function:
[tex]\[ f(-2) = -3(-2) + 3 \][/tex]
4. Multiply inside the function:
[tex]\[ -3(-2) = 6 \][/tex]
5. Add the remaining constant term:
[tex]\[ 6 + 3 = 9 \][/tex]
Hence, the value of [tex]\( f(-2) \)[/tex] is:
[tex]\[ f(-2) = 9 \][/tex]
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