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Sagot :
To find the equation of a circle with a given center and radius, we use the standard form equation of a circle:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
Here, [tex]\((h, k)\)[/tex] represents the coordinates of the center of the circle, and [tex]\(r\)[/tex] represents the radius.
Given:
- The center of the circle is [tex]\((-5, 2)\)[/tex], so [tex]\(h = -5\)[/tex] and [tex]\(k = 2\)[/tex].
- The radius of the circle is [tex]\(7\)[/tex], so [tex]\(r = 7\)[/tex].
Substitute the values of [tex]\(h\)[/tex], [tex]\(k\)[/tex], and [tex]\(r\)[/tex] into the standard form equation:
[tex]\[ (x - (-5))^2 + (y - 2)^2 = 7^2 \][/tex]
Simplify the equation:
[tex]\[ (x + 5)^2 + (y - 2)^2 = 49 \][/tex]
Thus, the correct equation of the circle is:
[tex]\[ (x + 5)^2 + (y - 2)^2 = 49 \][/tex]
Among the given options, the correct choice is:
[tex]\[ (x + 5)^2 + (y - 2)^2 = 49 \][/tex]
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
Here, [tex]\((h, k)\)[/tex] represents the coordinates of the center of the circle, and [tex]\(r\)[/tex] represents the radius.
Given:
- The center of the circle is [tex]\((-5, 2)\)[/tex], so [tex]\(h = -5\)[/tex] and [tex]\(k = 2\)[/tex].
- The radius of the circle is [tex]\(7\)[/tex], so [tex]\(r = 7\)[/tex].
Substitute the values of [tex]\(h\)[/tex], [tex]\(k\)[/tex], and [tex]\(r\)[/tex] into the standard form equation:
[tex]\[ (x - (-5))^2 + (y - 2)^2 = 7^2 \][/tex]
Simplify the equation:
[tex]\[ (x + 5)^2 + (y - 2)^2 = 49 \][/tex]
Thus, the correct equation of the circle is:
[tex]\[ (x + 5)^2 + (y - 2)^2 = 49 \][/tex]
Among the given options, the correct choice is:
[tex]\[ (x + 5)^2 + (y - 2)^2 = 49 \][/tex]
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