Get expert insights and community support for your questions on IDNLearn.com. Ask your questions and receive reliable, detailed answers from our dedicated community of experts.
Sagot :
¡Claro! Resolveré cada una de las multiplicaciones paso a paso:
### 1. [tex]\(1(-3a) \left(a^2\right)\)[/tex]
[tex]\[ 1 \cdot (-3a) \cdot a^2 = -3a \cdot a^2 = -3a^3 \][/tex]
### 2. [tex]\(\left(3x^2\right)\left(-x^3n\right)\)[/tex]
[tex]\[ 3x^2 \cdot (-x^3n) = 3 \cdot (-1) \cdot x^{2+3} \cdot n = -3x^5n \][/tex]
### 3. [tex]\(\left(-m^2n\right)\left(-3m^2\right)\)[/tex]
[tex]\[ (-m^2n) \cdot (-3m^2) = (-1) \cdot (-3) \cdot m^{2+2} \cdot n = 3m^4n \][/tex]
### 4. [tex]\((-5a^3y^2)\left(ay^2\right)\)[/tex]
[tex]\[ -5a^3y^2 \cdot ay^2 = -5 \cdot a^{3+1} \cdot y^{2+2} = -5a^4y^4 \][/tex]
### 5. [tex]\((-2ab)\left(-3a^2b^3\right)\)[/tex]
[tex]\[ (-2ab) \cdot (-3a^2b^3) = (-2) \cdot (-3) \cdot a^{1+2} \cdot b^{1+3} = 6a^3b^4 \][/tex]
### 6. [tex]\(\left(\frac{1}{2}x^3\right)\left(-\frac{2}{3}a^2x\right)\)[/tex]
[tex]\[ \left(\frac{1}{2}x^3\right) \cdot \left(-\frac{2}{3}a^2x\right) = \frac{1}{2} \cdot -\frac{2}{3} \cdot a^2 \cdot x^{3+1}\][/tex]
[tex]\[ = -\frac{2}{6}a^2x^4 = -\frac{1}{3}a^2x^4 \][/tex]
### 7. [tex]\(\left(\frac{2}{3}a^5\right)\left(\frac{2}{4}a^2b^4\right)\)[/tex]
[tex]\[ \left(\frac{2}{3}a^5\right) \cdot \left(\frac{2}{4}a^2b^4\right) = \frac{2}{3} \cdot \frac{1}{2} \cdot a^{5+2} \cdot b^4 = \frac{2 \cdot 1}{3 \cdot 2} a^7b^4\][/tex]
[tex]\[ = \frac{1}{3}a^7b^4 \][/tex]
### 8. [tex]\(8\left(-\frac{3}{5}m^2\right)\left(-5a^2m\right)\)[/tex]
[tex]\[ 8 \cdot \left(-\frac{3}{5}m^2\right) \cdot \left(-5a^2m\right) = 8 \cdot -\frac{3}{5} \cdot -5 \cdot a^2 \cdot m^{2+1} \][/tex]
[tex]\[ = 8 \cdot \frac{15}{5} \cdot a^2 m^3 = 8 \cdot 3 \cdot a^2 m^3 = 24a^2m^3 \][/tex]
### 9. [tex]\(q\left(-\frac{1}{2}x^2y\right)\left(-\frac{3}{5}xy^2\right)\)[/tex]
[tex]\[ q \cdot \left(-\frac{1}{2}x^2y\right) \cdot \left(-\frac{3}{5}xy^2\right) = q \cdot -\frac{1}{2} \cdot -\frac{3}{5} \cdot x^{2+1} \cdot y^{1+2} \][/tex]
[tex]\[ = q \cdot \frac{3}{10} \cdot x^3y^3 = \frac{3}{10}q x^3y^3 \][/tex]
### 10. [tex]\(0\left(-\frac{10}{3}x^3\right)\left(-\frac{3}{4}x^2y\right)\)[/tex]
[tex]\[ 0 \cdot \left(-\frac{10}{3}x^3\right) \cdot \left(-\frac{3}{4}x^2y\right) = 0 \][/tex]
En resumen, las soluciones son:
[tex]\[ \begin{array}{cc} -3a^3, & -3n x^5, \\ 3m^4 n, & -5a^4 y^4, \\ 6a^3b^4, & -\frac{1}{3}a^2x^4, \\ \frac{1}{3}a^7b^4, & 24a^2m^3, \\ 0.3qx^3y^3, & 0 \end{array} \][/tex]
### 1. [tex]\(1(-3a) \left(a^2\right)\)[/tex]
[tex]\[ 1 \cdot (-3a) \cdot a^2 = -3a \cdot a^2 = -3a^3 \][/tex]
### 2. [tex]\(\left(3x^2\right)\left(-x^3n\right)\)[/tex]
[tex]\[ 3x^2 \cdot (-x^3n) = 3 \cdot (-1) \cdot x^{2+3} \cdot n = -3x^5n \][/tex]
### 3. [tex]\(\left(-m^2n\right)\left(-3m^2\right)\)[/tex]
[tex]\[ (-m^2n) \cdot (-3m^2) = (-1) \cdot (-3) \cdot m^{2+2} \cdot n = 3m^4n \][/tex]
### 4. [tex]\((-5a^3y^2)\left(ay^2\right)\)[/tex]
[tex]\[ -5a^3y^2 \cdot ay^2 = -5 \cdot a^{3+1} \cdot y^{2+2} = -5a^4y^4 \][/tex]
### 5. [tex]\((-2ab)\left(-3a^2b^3\right)\)[/tex]
[tex]\[ (-2ab) \cdot (-3a^2b^3) = (-2) \cdot (-3) \cdot a^{1+2} \cdot b^{1+3} = 6a^3b^4 \][/tex]
### 6. [tex]\(\left(\frac{1}{2}x^3\right)\left(-\frac{2}{3}a^2x\right)\)[/tex]
[tex]\[ \left(\frac{1}{2}x^3\right) \cdot \left(-\frac{2}{3}a^2x\right) = \frac{1}{2} \cdot -\frac{2}{3} \cdot a^2 \cdot x^{3+1}\][/tex]
[tex]\[ = -\frac{2}{6}a^2x^4 = -\frac{1}{3}a^2x^4 \][/tex]
### 7. [tex]\(\left(\frac{2}{3}a^5\right)\left(\frac{2}{4}a^2b^4\right)\)[/tex]
[tex]\[ \left(\frac{2}{3}a^5\right) \cdot \left(\frac{2}{4}a^2b^4\right) = \frac{2}{3} \cdot \frac{1}{2} \cdot a^{5+2} \cdot b^4 = \frac{2 \cdot 1}{3 \cdot 2} a^7b^4\][/tex]
[tex]\[ = \frac{1}{3}a^7b^4 \][/tex]
### 8. [tex]\(8\left(-\frac{3}{5}m^2\right)\left(-5a^2m\right)\)[/tex]
[tex]\[ 8 \cdot \left(-\frac{3}{5}m^2\right) \cdot \left(-5a^2m\right) = 8 \cdot -\frac{3}{5} \cdot -5 \cdot a^2 \cdot m^{2+1} \][/tex]
[tex]\[ = 8 \cdot \frac{15}{5} \cdot a^2 m^3 = 8 \cdot 3 \cdot a^2 m^3 = 24a^2m^3 \][/tex]
### 9. [tex]\(q\left(-\frac{1}{2}x^2y\right)\left(-\frac{3}{5}xy^2\right)\)[/tex]
[tex]\[ q \cdot \left(-\frac{1}{2}x^2y\right) \cdot \left(-\frac{3}{5}xy^2\right) = q \cdot -\frac{1}{2} \cdot -\frac{3}{5} \cdot x^{2+1} \cdot y^{1+2} \][/tex]
[tex]\[ = q \cdot \frac{3}{10} \cdot x^3y^3 = \frac{3}{10}q x^3y^3 \][/tex]
### 10. [tex]\(0\left(-\frac{10}{3}x^3\right)\left(-\frac{3}{4}x^2y\right)\)[/tex]
[tex]\[ 0 \cdot \left(-\frac{10}{3}x^3\right) \cdot \left(-\frac{3}{4}x^2y\right) = 0 \][/tex]
En resumen, las soluciones son:
[tex]\[ \begin{array}{cc} -3a^3, & -3n x^5, \\ 3m^4 n, & -5a^4 y^4, \\ 6a^3b^4, & -\frac{1}{3}a^2x^4, \\ \frac{1}{3}a^7b^4, & 24a^2m^3, \\ 0.3qx^3y^3, & 0 \end{array} \][/tex]
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.
