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Charles and Cynthia are purchasing a house. They obtained a 30-year, \[tex]$535,000 mortgage at an annual interest rate of 3.6% compounded monthly.

Calculate their monthly payment on the loan. Round your answer to the nearest cent.

\[
M = \frac{P \left( \frac{r}{n} \right) \left( 1 + \frac{r}{n} \right)^{nt}}{\left( \left( 1 + \frac{r}{n} \right)^{nt} - 1 \right)}
\]

Their monthly payment will be \$[/tex] [tex]\(\square\)[/tex]


Sagot :

Let’s establish the known values first:
- Principal amount (loan amount): [tex]\( \$535,000 \)[/tex]
- Annual interest rate: [tex]\( 3.6\% \)[/tex] (0.036 as a decimal)
- Loan term: 30 years

To calculate the monthly payment, we can use the formula for the monthly mortgage payment:
[tex]\[ M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n - 1} \][/tex]
where:
- [tex]\( M \)[/tex] is the monthly payment,
- [tex]\( P \)[/tex] is the principal loan amount (\[tex]$535,000), - \( r \) is the monthly interest rate, - \( n \) is the number of payments (monthly payments over the loan term). First, calculate the monthly interest rate by dividing the annual interest rate by 12: \[ r = \frac{0.036}{12} = 0.003 \] Next, calculate the total number of payments over the loan term of 30 years: \[ n = 30 \times 12 = 360 \] Now, substitute the values into the formula: \[ M = \frac{535,000 \times 0.003 \times (1 + 0.003)^{360}}{(1 + 0.003)^{360} - 1} \] Simplify and solve the equation to find the monthly payment, which we'll denote as \( M \). After performing the calculations, you will find that the monthly mortgage payment \( M \) is: \[ M = \$[/tex]2432.35 \]

Therefore, the monthly payment on the loan will be \$2,432.35.
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