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Sagot :
To determine the stopping distance for an average freight train traveling at 30 miles per hour (MPH), we need to analyze the options provided and find which one matches the given condition.
The options are:
A. 1 mile
B. [tex]\( \frac{3}{4} \)[/tex] mile
C. [tex]\( \frac{1}{2} \)[/tex] mile
D. [tex]\( \frac{1}{4} \)[/tex] mile
Based on our analysis, the stopping distance for an average freight train traveling at 30 MPH is [tex]\( 0.75 \)[/tex] mile.
Now, let's compare this distance with each of the given options:
- Option A. 1 mile: 0.75 mile is less than 1 mile.
- Option B. [tex]\( \frac{3}{4} \)[/tex] mile: 0.75 mile equals [tex]\( \frac{3}{4} \)[/tex] mile.
- Option C. [tex]\( \frac{1}{2} \)[/tex] mile: 0.75 mile is more than [tex]\( \frac{1}{2} \)[/tex] mile.
- Option D. [tex]\( \frac{1}{4} \)[/tex] mile: 0.75 mile is more than [tex]\( \frac{1}{4} \)[/tex] mile.
From this comparison, we can see that option B ( [tex]\( \frac{3}{4} \)[/tex] mile) accurately represents the stopping distance for the freight train.
Therefore, the correct answer is:
B. [tex]\( \frac{3}{4} \)[/tex] mile
The options are:
A. 1 mile
B. [tex]\( \frac{3}{4} \)[/tex] mile
C. [tex]\( \frac{1}{2} \)[/tex] mile
D. [tex]\( \frac{1}{4} \)[/tex] mile
Based on our analysis, the stopping distance for an average freight train traveling at 30 MPH is [tex]\( 0.75 \)[/tex] mile.
Now, let's compare this distance with each of the given options:
- Option A. 1 mile: 0.75 mile is less than 1 mile.
- Option B. [tex]\( \frac{3}{4} \)[/tex] mile: 0.75 mile equals [tex]\( \frac{3}{4} \)[/tex] mile.
- Option C. [tex]\( \frac{1}{2} \)[/tex] mile: 0.75 mile is more than [tex]\( \frac{1}{2} \)[/tex] mile.
- Option D. [tex]\( \frac{1}{4} \)[/tex] mile: 0.75 mile is more than [tex]\( \frac{1}{4} \)[/tex] mile.
From this comparison, we can see that option B ( [tex]\( \frac{3}{4} \)[/tex] mile) accurately represents the stopping distance for the freight train.
Therefore, the correct answer is:
B. [tex]\( \frac{3}{4} \)[/tex] mile
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