Certainly! Let's go through each missing part step-by-step.
### Acid and Conjugate Base Table
1. Given:
- Acid: [tex]\(H_3O^+\)[/tex]
- Conjugate Base: [tex]\(H_2O\)[/tex]
The conjugate base of [tex]\(H_3O^+\)[/tex] is [tex]\(H_2O\)[/tex].
2. Needed:
- Acid: [tex]\(NH_4^+\)[/tex]
- Conjugate Base: ?
When [tex]\(NH_4^+\)[/tex] loses a proton ([tex]\(H^+\)[/tex]), it forms [tex]\(NH_3\)[/tex].
Hence, the conjugate base of [tex]\(NH_4^+\)[/tex] is [tex]\(NH_3\)[/tex].
3. Needed:
- Acid: [tex]\(H_2O\)[/tex]
- Conjugate Base: ?
When [tex]\(H_2O\)[/tex] loses a proton ([tex]\(H^+\)[/tex]), it forms [tex]\(OH^-\)[/tex].
Hence, the conjugate base of [tex]\(H_2O\)[/tex] is [tex]\(OH^-\)[/tex].
So, we can now fill in the table:
\begin{tabular}{|c|c|}
\hline
acid & conjugate base \\
\hline
[tex]$H_3O^{+}$[/tex] & [tex]$H_2O$[/tex] \\
\hline
[tex]$NH_4^{+}$[/tex] & [tex]$NH_3$[/tex] \\
\hline
[tex]$H_2O$[/tex] & [tex]$OH^-$[/tex] \\
\hline
\end{tabular}
### Base and Conjugate Acid Table
1. Needed:
- Base: [tex]\(OH^-\)[/tex]
- Conjugate Acid: ?
When [tex]\(OH^-\)[/tex] gains a proton ([tex]\(H^+\)[/tex]), it forms [tex]\(H_2O\)[/tex].
Hence, the conjugate acid of [tex]\(OH^-\)[/tex] is [tex]\(H_2O\)[/tex].
2. Needed:
- Base: [tex]\(SO_4^{2-}\)[/tex]
- Conjugate Acid: ?
When [tex]\(SO_4^{2-}\)[/tex] gains a proton ([tex]\(H^+\)[/tex]), it forms [tex]\(HSO_4^-\)[/tex].
Hence, the conjugate acid of [tex]\(SO_4^{2-}\)[/tex] is [tex]\(HSO_4^-\)[/tex].
3. Needed:
- Base: [tex]\(NH_3\)[/tex]
- Conjugate Acid: ?
When [tex]\(NH_3\)[/tex] gains a proton ([tex]\(H^+\)[/tex]), it forms [tex]\(NH_4^+\)[/tex].
Hence, the conjugate acid of [tex]\(NH_3\)[/tex] is [tex]\(NH_4^+\)[/tex].
So, we can now fill in the table:
\begin{tabular}{|c|c|}
\hline
base & conjugate acid \\
\hline
[tex]$OH^-$[/tex] & [tex]$H_2O$[/tex] \\
\hline
[tex]$SO_4^{2-}$[/tex] & [tex]$HSO_4^-$[/tex] \\
\hline
[tex]$NH_3$[/tex] & [tex]$NH_4^+$[/tex] \\
\hline
\end{tabular}
These are the missing chemical formulae for the given tables.
