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What is the mass percent of sulfur in compound [tex]\( A \)[/tex]?

\begin{tabular}{|c|c|c|c|}
\hline
Sample & \begin{tabular}{c}
Total Mass \\
( g )
\end{tabular} & \begin{tabular}{c}
Mass S \\
( g )
\end{tabular} & \begin{tabular}{c}
Mass O \\
( g )
\end{tabular} \\
\hline
A & 80.0 & 32.0 & 48.0 \\
\hline
B & 60.0 & 30.0 & 30.0 \\
\hline
\end{tabular}

\% sulfur in [tex]\( A \)[/tex]:


Sagot :

To find the mass percent of sulfur in compound [tex]\( A \)[/tex], follow these steps:

1. Identify the given values:
- Total mass of compound [tex]\( A \)[/tex] = 80.0 grams
- Mass of sulfur in compound [tex]\( A \)[/tex] = 32.0 grams

2. Write down the formula for the mass percent of sulfur:
[tex]\[ \text{Mass percent of sulfur} = \left( \frac{\text{Mass of sulfur}}{\text{Total mass of the compound}} \right) \times 100 \][/tex]

3. Substitute the given values into the formula:
[tex]\[ \text{Mass percent of sulfur} = \left( \frac{32.0 \text{ grams}}{80.0 \text{ grams}} \right) \times 100 \][/tex]

4. Perform the division:
[tex]\[ \frac{32.0}{80.0} = 0.4 \][/tex]

5. Multiply by 100 to convert the fraction to a percentage:
[tex]\[ 0.4 \times 100 = 40.0 \][/tex]

Therefore, the mass percent of sulfur in compound [tex]\( A \)[/tex] is [tex]\(\boxed{40.0 \% }\)[/tex].