IDNLearn.com offers a comprehensive platform for finding and sharing knowledge. Join our community to receive prompt and reliable responses to your questions from experienced professionals.
Sagot :
To determine whether [tex]\( f(x) \)[/tex] is a function, we must verify if each input value [tex]\( x \)[/tex] maps to exactly one output value [tex]\( f(x) \)[/tex]. In other words, for every unique [tex]\( x \)[/tex], there must be a unique and consistent [tex]\( f(x) \)[/tex].
Let's go through the given values step-by-step:
1. We are given the input values [tex]\( x \)[/tex] as follows: [tex]\( 0, 4, 82, 12, 3, 2, 0 \)[/tex].
2. We are also given the output values [tex]\( f(x) \)[/tex] as follows: [tex]\( 4, 82, 12, 3, 2, 0 \)[/tex].
Next, we check if each input [tex]\( x \)[/tex] corresponds to a unique [tex]\( f(x) \)[/tex]:
- The input [tex]\( x = 0 \)[/tex] appears twice in the list of inputs.
When [tex]\( x = 0 \)[/tex] appears more than once, for [tex]\( f(x) \)[/tex] to be qualified as a function, the corresponding output [tex]\( f(x) \)[/tex] for each occurrence of [tex]\( x = 0 \)[/tex] must be the same. However, in this problem setup, we are more concerned about whether any input [tex]\( x \)[/tex] is repeated in the set of inputs.
Since we have repeated values of [tex]\( x = 0 \)[/tex]:
- This repetition indicates that not every input [tex]\( x \)[/tex] has a unique mapping, or it raises a suspicion regarding the output mappings corresponding to the repeated input.
Consequently, with the presence of a duplicate input value [tex]\( x = 0 \)[/tex] in the list, we cannot guarantee that [tex]\( f(x) \)[/tex] is a function.
Thus, based on the given values, the answer to whether [tex]\( f(x) \)[/tex] is a function is:
A. False.
Therefore, the true result is [tex]\( \boxed{A} \)[/tex].
Let's go through the given values step-by-step:
1. We are given the input values [tex]\( x \)[/tex] as follows: [tex]\( 0, 4, 82, 12, 3, 2, 0 \)[/tex].
2. We are also given the output values [tex]\( f(x) \)[/tex] as follows: [tex]\( 4, 82, 12, 3, 2, 0 \)[/tex].
Next, we check if each input [tex]\( x \)[/tex] corresponds to a unique [tex]\( f(x) \)[/tex]:
- The input [tex]\( x = 0 \)[/tex] appears twice in the list of inputs.
When [tex]\( x = 0 \)[/tex] appears more than once, for [tex]\( f(x) \)[/tex] to be qualified as a function, the corresponding output [tex]\( f(x) \)[/tex] for each occurrence of [tex]\( x = 0 \)[/tex] must be the same. However, in this problem setup, we are more concerned about whether any input [tex]\( x \)[/tex] is repeated in the set of inputs.
Since we have repeated values of [tex]\( x = 0 \)[/tex]:
- This repetition indicates that not every input [tex]\( x \)[/tex] has a unique mapping, or it raises a suspicion regarding the output mappings corresponding to the repeated input.
Consequently, with the presence of a duplicate input value [tex]\( x = 0 \)[/tex] in the list, we cannot guarantee that [tex]\( f(x) \)[/tex] is a function.
Thus, based on the given values, the answer to whether [tex]\( f(x) \)[/tex] is a function is:
A. False.
Therefore, the true result is [tex]\( \boxed{A} \)[/tex].
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.