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Mrs. Li baked cookies for sale at a school event. [tex]\(\frac{3}{4}\)[/tex] of the cookies were chocolate cookies and the rest were vanilla cookies. She sold [tex]\(\frac{1}{2}\)[/tex] of the total number of cookies. [tex]\(\frac{5}{6}\)[/tex] of the cookies sold were chocolate cookies. There were 18 vanilla cookies left. How many chocolate cookies were not sold?

Sagot :

Let's work through this step-by-step:

1. Determine the fractions involved:
- From the problem, [tex]$\frac{3}{4}$[/tex] of the cookies were chocolate cookies.
- Therefore, [tex]$\frac{1}{4}$[/tex] of the cookies were vanilla cookies.

2. Define the variables:
Let [tex]\( T \)[/tex] be the total number of cookies baked.

- Chocolate cookies: [tex]\( \frac{3}{4}T \)[/tex]
- Vanilla cookies: [tex]\( \frac{1}{4}T \)[/tex]

3. Relate the vanilla cookies to the total cookies:
- We're given that 18 vanilla cookies were left.
- Knowing Mrs. Li sold [tex]$\frac{1}{2}$[/tex] of the total cookies, she also kept [tex]$\frac{1}{2}$[/tex] of the total cookies. Thus, the remaining vanilla cookies are half of the originally baked vanilla cookies.

4. Set up the equation for vanilla cookies:
[tex]\[ \text{Vanilla cookies left} = \left( \text{Vanilla cookies originally baked} \right) \times \left(\text{Fraction of unsold cookies}\right) \][/tex]
Given there were 18 vanilla cookies left:
[tex]\[ 18 = \left( \frac{1}{4}T \right) \times \left( \frac{1}{2} \right) \][/tex]

5. Solve for [tex]\( T \)[/tex]:
[tex]\[ 18 = \frac{1}{8}T \][/tex]
[tex]\[ T = 18 \times 8 \][/tex]
[tex]\[ T = 144 \][/tex]

6. Determine the number of chocolate cookies:
[tex]\[ \text{Chocolate cookies} = \frac{3}{4}T = \frac{3}{4} \times 144 = 108 \][/tex]

7. Determine the number of cookies sold:
[tex]\[ \text{Total cookies sold} = \frac{1}{2}T = \frac{1}{2} \times 144 = 72 \][/tex]

8. Determine how many of the sold cookies were chocolate:
[tex]\[ \text{Chocolate cookies sold} = \frac{5}{6} \times \text{Total cookies sold} = \frac{5}{6} \times 72 = 60 \][/tex]

9. Determine how many chocolate cookies were not sold:
[tex]\[ \text{Chocolate cookies not sold} = \text{Total chocolate cookies} - \text{Chocolate cookies sold} \][/tex]
[tex]\[ \text{Chocolate cookies not sold} = 108 - 60 = 48 \][/tex]

Therefore, the number of chocolate cookies that were not sold is [tex]\( 48 \)[/tex].