Sure, let's go through the reaction step by step to identify the spectator ions. The given reaction is:
[tex]\[ 2 H ^{+}+ CO _3{ }^{2-}+2 Na ^{+}+2 OH ^{-} \rightarrow 2 Na ^{+}+ CO _3{ }^{2-}+2 H _2 O \][/tex]
1. First, let's list the reactants:
- [tex]\(2 H^+\)[/tex]
- [tex]\(CO_3^{2-}\)[/tex]
- [tex]\(2 Na^+\)[/tex]
- [tex]\(2 OH^-\)[/tex]
2. Next, let's list the products:
- [tex]\(2 Na^+\)[/tex]
- [tex]\(CO_3^{2-}\)[/tex]
- [tex]\(2 H_2O\)[/tex]
3. Identifying spectator ions:
- Spectator ions are ions that do not participate in the reaction; they remain unchanged on both reactant and product sides.
- Inspect the reaction to see which ions remain unchanged.
4. Compare the ions:
- [tex]\(H^+\)[/tex]: Present in reactants but reacts to form water, so it's not a spectator ion.
- [tex]\(CO_3^{2-}\)[/tex]: Present in both reactants and products and remains unchanged. This is a spectator ion.
- [tex]\(Na^+\)[/tex]: Present in both reactants and products and remains unchanged. This is a spectator ion.
- [tex]\(OH^-\)[/tex]: Present in reactants but reacts to form water, so it's not a spectator ion.
- [tex]\(2 H_2O\)[/tex]: This is a product formed during the reaction, not an ion, thus not a spectator ion.
After analyzing the reaction, we determine that the spectator ions are:
[tex]\[
CO_3^{2-} \quad \text{and} \quad Na^+
\][/tex]
Therefore, the spectator ions in this reaction are [tex]\(CO_3^{2-}\)[/tex] and [tex]\(Na^+\)[/tex].
