Explore a world of knowledge and get your questions answered on IDNLearn.com. Discover prompt and accurate answers from our experts, ensuring you get the information you need quickly.

5. What is the remainder when [tex]x^4 + 3x^2 - 5x^2 + 6x = 3[/tex] is divided by [tex]x - 2[/tex]?

Sagot :

Sure, let's solve the problem step by step.

1. Understand the polynomial and simplify if necessary:
Given: [tex]\( P(x) = x^4 + 3x^2 - 5x^2 + 6x \)[/tex]

First, simplify the polynomial:
[tex]\[ P(x) = x^4 + (3x^2 - 5x^2) + 6x \][/tex]
[tex]\[ P(x) = x^4 - 2x^2 + 6x \][/tex]

2. Substitute [tex]\( x = 2 \)[/tex] into the polynomial:
[tex]\[ P(2) = (2)^4 - 2(2)^2 + 6(2) \][/tex]
[tex]\[ P(2) = 16 - 2 \cdot 4 + 12 \][/tex]
[tex]\[ P(2) = 16 - 8 + 12 \][/tex]
[tex]\[ P(2) = 20 \][/tex]

3. Given the equation [tex]\( P(x) = 3 \)[/tex] and need to find the remainder when substituting [tex]\( x = 2 \)[/tex]:
The polynomial equation at [tex]\( x = 2 \)[/tex] must satisfy:
[tex]\[ P(2) = 3 \][/tex]

4. Calculate the remainder by subtracting 3 from [tex]\( P(2) \)[/tex]:
We have already found [tex]\( P(2) = 20 \)[/tex], so the remainder is:
[tex]\[ \text{Remainder} = P(2) - 3 \][/tex]
[tex]\[ \text{Remainder} = 20 - 3 \][/tex]
[tex]\[ \text{Remainder} = 17 \][/tex]

Therefore, the value of the polynomial at [tex]\( x = 2 \)[/tex] is 20, and the remainder when the polynomial is set to 3 and [tex]\( x = 2 \)[/tex] is substituted is 17.