Certainly! Let's solve the problem step by step.
First, evaluate the initial cross:
1. A pea plant with genotype PP (purple flowers) mates with a plant with genotype pp (white flowers).
2. P (purple) is dominant over p (white). The offspring from this cross will all have the genotype Pp (heterozygous purple flowers) because each offspring gets one allele from each parent.
Next, evaluate the second cross:
3. One of the Pp offspring mates with another pp (white flower).
4. Construct the Punnett Square for this cross:
[tex]\[
\begin{array}{|c|c|c|}
\hline & P & p \\
\hline p & Pp & pp \\
\hline p & Pp & pp \\
\hline
\end{array}
\][/tex]
From this Punnett Square, you can see the genotypes of the offspring from this cross:
- 2 out of 4 (or 50%) will be Pp (heterozygous purple).
- 2 out of 4 (or 50%) will be pp (homozygous white).
5. We're asked to determine the probability of the offspring being homozygous dominant (PP). Look at the results:
- There are no homozygous dominant PP offspring from this cross.
- Thus, the possibility of an offspring being homozygous dominant (PP) is 0% because none of the combinations produce a PP genotype.
Now, filling the given sentences with the correct information:
1. The possibility that the offspring will have purple flowers from the initial PP x pp cross is 100%.
2. If an offspring from this cross mates with a pp, the possibility of a homozygous dominant genotype (PP) is 0%.
So, the correctly selected options in the drop-down menus should be:
- First drop-down menu: 100%.
- Second drop-down menu: 0%, because none of the offspring from the second cross had a homozygous dominant genotype.
