From health tips to tech hacks, find it all on IDNLearn.com. Ask anything and receive thorough, reliable answers from our community of experienced professionals.
Sagot :
To find the expression [tex]\(\tan^3 \theta - \cot^3 \theta\)[/tex], we can proceed as follows:
1. Understand the individual components:
- [tex]\(\tan^3 \theta\)[/tex] is the tangent of [tex]\(\theta\)[/tex] raised to the power of 3.
- [tex]\(\cot^3 \theta\)[/tex] is the cotangent of [tex]\(\theta\)[/tex] raised to the power of 3. Recall that cotangent is the reciprocal of the tangent function, i.e., [tex]\(\cot \theta = \frac{1}{\tan \theta}\)[/tex].
2. Express [tex]\(\cot^3 \theta\)[/tex]in terms of [tex]\(\tan \theta\)[/tex]:
[tex]\[ \cot^3 \theta = \left( \frac{1}{\tan \theta} \right)^3 = \frac{1}{\tan^3 \theta} \][/tex]
3. Substitute back into the original expression:
[tex]\[ \tan^3 \theta - \cot^3 \theta = \tan^3 \theta - \frac{1}{\tan^3 \theta} \][/tex]
Therefore, [tex]\(\tan^3 \theta - \cot^3 \theta\)[/tex] simplifies to:
[tex]\[ \tan^3 \theta - \frac{1}{\tan^3 \theta} \][/tex]
1. Understand the individual components:
- [tex]\(\tan^3 \theta\)[/tex] is the tangent of [tex]\(\theta\)[/tex] raised to the power of 3.
- [tex]\(\cot^3 \theta\)[/tex] is the cotangent of [tex]\(\theta\)[/tex] raised to the power of 3. Recall that cotangent is the reciprocal of the tangent function, i.e., [tex]\(\cot \theta = \frac{1}{\tan \theta}\)[/tex].
2. Express [tex]\(\cot^3 \theta\)[/tex]in terms of [tex]\(\tan \theta\)[/tex]:
[tex]\[ \cot^3 \theta = \left( \frac{1}{\tan \theta} \right)^3 = \frac{1}{\tan^3 \theta} \][/tex]
3. Substitute back into the original expression:
[tex]\[ \tan^3 \theta - \cot^3 \theta = \tan^3 \theta - \frac{1}{\tan^3 \theta} \][/tex]
Therefore, [tex]\(\tan^3 \theta - \cot^3 \theta\)[/tex] simplifies to:
[tex]\[ \tan^3 \theta - \frac{1}{\tan^3 \theta} \][/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.