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Sagot :
Answer: (c) 104____2
Step-by-step explanation:
To determine the smallest digit that can be filled in to make each number divisible by 4, we need to check the last two digits of each number.
Let's go through each option:
**(a) 63**
Last two digits: 63
To make 63 divisible by 4, we need the last two digits to form a number divisible by 4. Here, 63 is not divisible by 4.
**(b) 345**
Last two digits: 45
To make 345 divisible by 4, we need the last two digits (45) to form a number divisible by 4. 45 is not divisible by 4.
**(c) 104___2**
Last two digits: 2
To make 104___2 divisible by 4, we need to check if 102 is divisible by 4 (since the last two digits are 02).
102 ÷ 4 = 25.5 (not an integer, so 102 is not divisible by 4)
Next, we need to find the smallest digit to fill in the blank:
The smallest digit that, when added to 102, makes the resulting number divisible by 4 is 2.
So, the answer is (c) 1042.
**(d) 56___32**
Last two digits: 32
To make 56___32 divisible by 4, we need to check if 32 is divisible by 4.
32 ÷ 4 = 8 (an integer, so 32 is divisible by 4)
Therefore, no additional digit is needed in this case.
After evaluating all the options, the correct answer is:
(c) 104____2
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