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1.1 How many moles of [tex]$H_2O$[/tex] will be produced from 6 moles of [tex]$O_2$[/tex]?

1.2 How many moles of [tex][tex]$H_2$[/tex][/tex] will react with 40 g of [tex]$O_2$[/tex]?

1.3 How many grams of [tex]$H_2O$[/tex] will be produced by 18 g of [tex][tex]$H_2$[/tex][/tex]?

Sagot :

GinnyAnsweridn
Sure, let's go through each part of the question step by step.

### Part 1.1: Moles of H₂O Produced from 6 Moles of O₂

Question:
How many moles of H₂O will be produced from 6 moles of O₂?

Solution:
The balanced chemical equation for the reaction between hydrogen and oxygen to form water is:
[tex]\[ 2H_2 + O_2 \rightarrow 2H_2O \][/tex]

According to this equation, 1 mole of O₂ produces 2 moles of H₂O. Therefore, if we have 6 moles of O₂, the number of moles of H₂O produced can be calculated as follows:
[tex]\[ \text{Moles of } H_2O = 6 \text{ moles of } O_2 \times 2 = 12 \text{ moles of } H_2O \][/tex]

So, 12 moles of H₂O will be produced from 6 moles of O₂.

### Part 1.2: Moles of H₂ Required to React with 40 g of O₂

Question:
How many moles of H₂ will react with 40 g of O₂?

Solution:
First, we need to find out how many moles of O₂ are present in 40 g. The molar mass of O₂ is 32 g/mol.

[tex]\[ \text{Moles of } O_2 = \frac{\text{Mass of } O_2}{\text{Molar mass of } O_2} = \frac{40 \text{ g}}{32 \text{ g/mol}} = 1.25 \text{ moles} \][/tex]

According to the balanced chemical equation, 1 mole of O₂ reacts with 2 moles of H₂. Therefore, we can calculate the moles of H₂ required as follows:
[tex]\[ \text{Moles of } H_2 = 1.25 \text{ moles of } O_2 \times 2 = 2.5 \text{ moles of } H_2 \][/tex]

So, 2.5 moles of H₂ will react with 40 g of O₂.

### Part 1.3: Grams of H₂O Produced by 18 g of H₂

Question:
How many grams of H₂O will be produced by 18 g of H₂?

Solution:
First, we need to determine the number of moles of H₂ in 18 g. The molar mass of H₂ is 2 g/mol.

[tex]\[ \text{Moles of } H_2 = \frac{\text{Mass of } H_2}{\text{Molar mass of } H_2} = \frac{18 \text{ g}}{2 \text{ g/mol}} = 9 \text{ moles} \][/tex]

From the balanced chemical equation, 2 moles of H₂ produce 2 moles of H₂O. Therefore, 9 moles of H₂ will produce 9 moles of H₂O.

Next, we need to convert the moles of H₂O to grams. The molar mass of H₂O is 18 g/mol.

[tex]\[ \text{Mass of } H_2O = \text{Moles of } H_2O \times \text{Molar mass of } H_2O = 9 \text{ moles} \times 18 \text{ g/mol} = 162 \text{ g} \][/tex]

So, 162 grams of H₂O will be produced by 18 grams of H₂.
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