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How much money will a borrower using Loan 1 pay in interest over the life of the loan?

\begin{tabular}{|l|r|r|}
\hline & \multicolumn{1}{|c|}{ Loan 1 } & \multicolumn{1}{c|}{ Loan 2 } \\
\hline Principal & [tex]$\$[/tex] 4600.00[tex]$ & $[/tex]\[tex]$ 4600.00$[/tex] \\
\hline Monthly Payment & [tex]$\$[/tex] 138.00[tex]$ & $[/tex]\[tex]$ 107.00$[/tex] \\
\hline Duration & 36 months & 48 months \\
\hline
\end{tabular}

[tex]$[?]$[/tex]
[tex]\[\square\][/tex]


Sagot :

To determine how much interest a borrower will pay on Loan 1 over the life of the loan, we'll need to follow a step-by-step approach.

### Step-by-Step Solution:

1. Identify the principal amount for Loan 1:

Principal amount is \[tex]$4600.00. 2. Identify the monthly payment for Loan 1: Monthly payment is \$[/tex]138.00.

3. Identify the duration of Loan 1:

Duration is 36 months.

4. Calculate the total amount paid by the borrower over the life of the loan:

To find the total amount paid, multiply the monthly payment by the number of payments (duration):

[tex]\[ \text{Total Payment} = \text{Monthly Payment} \times \text{Duration} \][/tex]

Plugging in the numbers:

[tex]\[ \text{Total Payment} = 138.00 \times 36 = \$4968.00 \][/tex]

5. Calculate the interest paid on Loan 1:

Interest paid is the total amount paid minus the principal amount:

[tex]\[ \text{Interest Paid} = \text{Total Payment} - \text{Principal} \][/tex]

Plugging in the numbers:

[tex]\[ \text{Interest Paid} = 4968.00 - 4600.00 = \$368.00 \][/tex]

Therefore, the borrower will pay \$368.00 in interest over the life of Loan 1.