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If [tex]$h(x) = 6 - x$[/tex], what is the value of [tex]$(h \circ h)(10)$[/tex]?

A. 16
B. 10
C. [tex]$-4$[/tex]
D. [tex]$-2$[/tex]


Sagot :

To find the value of [tex]\((h \circ h)(10)\)[/tex], we need to first determine [tex]\(h(10)\)[/tex] and then use that result to determine [tex]\(h(h(10))\)[/tex].

Given the function [tex]\(h(x) = 6 - x\)[/tex]:

1. Calculate [tex]\(h(10)\)[/tex]:
[tex]\[ h(10) = 6 - 10 = -4 \][/tex]

2. Now calculate [tex]\(h(h(10))\)[/tex], which is [tex]\(h(-4)\)[/tex]:
[tex]\[ h(-4) = 6 - (-4) = 6 + 4 = 10 \][/tex]

Therefore, the value of [tex]\((h \circ h)(10)\)[/tex] is [tex]\(10\)[/tex].

So the answer is:
[tex]\[ \boxed{10} \][/tex]