IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Join our knowledgeable community to find the answers you need for any topic or issue.

Find the LCD of the following expressions. Write the LCD in factored form.

[tex]\[
\frac{4}{n^2 + 5n - 36} \quad \text{and} \quad \frac{7n}{n^2 - 7n + 12}
\][/tex]

LCD: [tex]\(\square\)[/tex]


Sagot :

To find the Least Common Denominator (LCD) of the given expressions:

[tex]\[ \frac{4}{n^2 + 5n - 36} \][/tex]
[tex]\[ \frac{7n}{n^2 - 7n + 12} \][/tex]

we follow these steps:

1. Factorize each denominator separately.

First denominator: [tex]\( n^2 + 5n - 36 \)[/tex]

To factorize this quadratic expression, we need to find two numbers that multiply to [tex]\(-36\)[/tex] (the constant term) and add to [tex]\(5\)[/tex] (the coefficient of [tex]\(n\)[/tex]).

These numbers are [tex]\(9\)[/tex] and [tex]\(-4\)[/tex]:

[tex]\[ n^2 + 5n - 36 = (n + 9)(n - 4) \][/tex]

So, the first denominator factors as:

[tex]\[ n^2 + 5n - 36 = (n - 4)(n + 9) \][/tex]

Second denominator: [tex]\( n^2 - 7n + 12 \)[/tex]

To factorize this quadratic expression, we need to find two numbers that multiply to [tex]\(12\)[/tex] (the constant term) and add to [tex]\(-7\)[/tex] (the coefficient of [tex]\(n\)[/tex]).

These numbers are [tex]\(-3\)[/tex] and [tex]\(-4\)[/tex]:

[tex]\[ n^2 - 7n + 12 = (n - 3)(n - 4) \][/tex]

So, the second denominator factors as:

[tex]\[ n^2 - 7n + 12 = (n - 4)(n - 3) \][/tex]

2. Identify all unique factors from both denominators.

For the denominators:

[tex]\[ n^2 + 5n - 36 = (n - 4)(n + 9) \][/tex]

and

[tex]\[ n^2 - 7n + 12 = (n - 4)(n - 3) \][/tex]

The unique factors are:
- [tex]\( (n - 4) \)[/tex]
- [tex]\( (n + 9) \)[/tex]
- [tex]\( (n - 3) \)[/tex]

3. Construct the Least Common Denominator (LCD).

The LCD is the product of the highest powers of all unique factors identified. Since we have:

[tex]\[ n^2 + 5n - 36 = (n - 4)(n + 9) \][/tex]

and

[tex]\[ n^2 - 7n + 12 = (n - 4)(n - 3) \][/tex]

The LCD must include each unique factor, appearing as many times as it does in any one denominator.

Therefore, we include each factor [tex]\( (n - 4) \)[/tex], [tex]\( (n + 9) \)[/tex], and [tex]\( (n - 3) \)[/tex]:

[tex]\[ \text{LCD} = (n - 4)(n - 3)(n + 9) \][/tex]

In conclusion, the Least Common Denominator (LCD) of the given expressions is:

[tex]\[ \boxed{(n - 4)(n - 3)(n + 9)} \][/tex]