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Which of the expressions below can be factored using the difference of squares method?

A. [tex]9x - 16y[/tex]

B. [tex]9x^2 - 16y^2[/tex]

C. [tex]9x^2 + 16y^2[/tex]

D. [tex]9x + 16y[/tex]


Sagot :

To determine which of the given expressions can be factored using the difference of squares method, let’s review the difference of squares formula:

[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]

We need to identify the expression that fits this pattern. Let’s examine each option:

Option A: [tex]\( 9x - 16y \)[/tex]

This expression has two terms: [tex]\( 9x \)[/tex] and [tex]\( 16y \)[/tex]. However, neither term is a perfect square, and it does not fit the form [tex]\( a^2 - b^2 \)[/tex]. Therefore, it cannot be factored using the difference of squares method.

Option B: [tex]\( 9x^2 - 16y^2 \)[/tex]

This is a two-term expression. Let’s check if each term is a perfect square:
- [tex]\( 9x^2 = (3x)^2 \)[/tex]
- [tex]\( 16y^2 = (4y)^2 \)[/tex]

Both terms are perfect squares. This fits the form [tex]\( a^2 - b^2 \)[/tex] where [tex]\( a = 3x \)[/tex] and [tex]\( b = 4y \)[/tex]. We can factor it as:

[tex]\[ 9x^2 - 16y^2 = (3x)^2 - (4y)^2 = (3x - 4y)(3x + 4y) \][/tex]

So, option B can be factored using the difference of squares method.

Option C: [tex]\( 9x^2 + 16y^2 \)[/tex]

This expression has two terms: [tex]\( 9x^2 \)[/tex] and [tex]\( 16y^2 \)[/tex], both of which are perfect squares. However, it involves a sum of squares, not a difference. The difference of squares method does not apply to sums of squares. Therefore, it cannot be factored using the difference of squares method.

Option D: [tex]\( 9x + 16y \)[/tex]

This expression has two terms: [tex]\( 9x \)[/tex] and [tex]\( 16y \)[/tex]. Neither term is a perfect square, and it does not fit the form [tex]\( a^2 - b^2 \)[/tex]. Therefore, it cannot be factored using the difference of squares method.

Based on the analysis, only option B can be factored using the difference of squares method. The answer is:

[tex]\[ \boxed{B} \][/tex]