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What is the volume of [tex]0.58[/tex] moles of [tex]H_2[/tex] gas at STP?

Sagot :

To determine the volume of 0.58 moles of [tex]\( H_2 \)[/tex] gas at Standard Temperature and Pressure (STP), we'll follow these steps:

1. Understand the concept: At STP (Standard Temperature and Pressure, which is defined as 0°C or 273.15K and 1 atm pressure), one mole of any ideal gas occupies 22.414 liters. This is a standard value used in chemistry.

2. Given data: We have 0.58 moles of [tex]\( H_2 \)[/tex] gas.

3. Use the molar volume of a gas at STP: According to the given standard, 1 mole of any gas occupies 22.414 liters at STP.

4. Set up the calculation: To find the volume occupied by 0.58 moles of [tex]\( H_2 \)[/tex] gas, multiply the number of moles by the volume per mole.

[tex]\[ \text{Volume of } H_2 \text{ gas} = \text{number of moles} \times \text{volume per mole at STP} \][/tex]

5. Substitute the values:
[tex]\[ \text{Volume of } H_2 \text{ gas} = 0.58 \text{ moles} \times 22.414 \text{ liters/mole} \][/tex]

6. Compute the result:
[tex]\[ \text{Volume of } H_2 \text{ gas} = 13.00012 \text{ liters} \][/tex]

7. Conclusion: Therefore, the volume of 0.58 moles of [tex]\( H_2 \)[/tex] gas at STP is 13.00012 liters.