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Assuming the compound is dissolved in water, what is the formula for phosphorous acid?

\begin{tabular}{|c|c|}
\hline
Name & Symbol \\
\hline
phosphate & [tex]$PO_4^{3-}$[/tex] \\
\hline
phosphite & [tex]$PO_3^{3-}$[/tex] \\
\hline
phosphorus & P \\
\hline
\end{tabular}

A. [tex]$H_3P$[/tex]
B. [tex]$H_3PO_4$[/tex]
C. HP
D. [tex]$H_3PO_3$[/tex]

Sagot :

GinnyAnsweridn
To determine the formula for phosphorous acid, we need to understand the relationship between phosphorous acid and its corresponding anion. Here’s the step-by-step process:

1. Identify the Relevant Anions:
- Phosphate: [tex]\( PO_4^{3-} \)[/tex]
- Phosphite: [tex]\( PO_3^{3-} \)[/tex]

2. Determine the Relevant Anionic Form for Phosphorous Acid:
- Phosphorous acid typically relates to the phosphite ion.

3. Construct the Acid Formula:
- Phosphorous acid will have the formula corresponding to the phosphite ion [tex]\( PO_3^{3-} \)[/tex].
- Since the phosphite ion has a charge of [tex]\(-3\)[/tex], to balance this charge, it requires three hydrogen ions [tex]\( H^+ \)[/tex].

4. Combine the Hydrogen Ions with the Phosphite Ion:
- Adding three hydrogen ions [tex]\( H^+ \)[/tex] to phosphite [tex]\( PO_3^{3-} \)[/tex] forms the phosphorous acid [tex]\( H_3PO_3 \)[/tex].

Thus, the formula for phosphorous acid is [tex]\( H_3PO_3 \)[/tex].

Therefore, the correct answer is:

[tex]\[ H_3PO_3 \][/tex]
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