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What is the volume of a right circular cone that has a height of 7.2 centimeters and a radius of 2.5 centimeters, to the nearest tenth of a cubic centimeter?

Sagot :

To find the volume of a right circular cone with a given height and radius, we use the formula for the volume of a cone, which is:

[tex]\[ V = \frac{1}{3} \pi r^2 h \][/tex]

where:
- [tex]\( V \)[/tex] is the volume of the cone,
- [tex]\( r \)[/tex] is the radius of the base of the cone,
- [tex]\( h \)[/tex] is the height of the cone,
- [tex]\( \pi \)[/tex] (pi) is a constant approximately equal to 3.14159.

Given:
- The height [tex]\( h = 7.2 \)[/tex] centimeters,
- The radius [tex]\( r = 2.5 \)[/tex] centimeters.

Let's substitute the given values into the formula:

[tex]\[ V = \frac{1}{3} \pi (2.5)^2 (7.2) \][/tex]

First, calculate the square of the radius:

[tex]\[ (2.5)^2 = 6.25 \][/tex]

Now substitute this back into the formula:

[tex]\[ V = \frac{1}{3} \pi (6.25) (7.2) \][/tex]

Next, multiply 6.25 and 7.2:

[tex]\[ 6.25 \times 7.2 = 45 \][/tex]

Now our equation looks like this:

[tex]\[ V = \frac{1}{3} \pi (45) \][/tex]

Multiply 45 by [tex]\(\pi\)[/tex]:

[tex]\[ \pi (45) \approx 141.3716694115407 \][/tex]

Now, divide by 3 to get the volume:

[tex]\[ V = \frac{141.3716694115407}{3} \approx 47.1238898038469 \][/tex]

The volume calculated is approximately 47.1238898038469 cubic centimeters.

To express this volume to the nearest tenth, we round 47.1238898038469 to one decimal place:

[tex]\[ V \approx 47.1 \][/tex]

Therefore, the volume of the right circular cone, to the nearest tenth of a cubic centimeter, is:

[tex]\[ 47.1 \][/tex]

So, the final answer is 47.1 cubic centimeters.