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Which numbers are the extremes of the proportion shown below?

[tex]\frac{3}{4} = \frac{6}{8}[/tex]

A. 3 and 6
B. 4 and 8
C. 4 and 6
D. 3 and 8


Sagot :

Let's analyze the proportion given:

[tex]\[ \frac{3}{4} = \frac{6}{8} \][/tex]

In a proportion [tex]\(\frac{a}{b} = \frac{c}{d}\)[/tex], the terms [tex]\(a\)[/tex] and [tex]\(d\)[/tex] are called the "extremes", and the terms [tex]\(b\)[/tex] and [tex]\(c\)[/tex] are referred to as the "means".

For the proportion given:

[tex]\[ \frac{3}{4} = \frac{6}{8} \][/tex]

The first term [tex]\(a\)[/tex] is 3, the second term [tex]\(b\)[/tex] is 4, the third term [tex]\(c\)[/tex] is 6, and the fourth term [tex]\(d\)[/tex] is 8. According to the definition of extremes, the extremes in this proportion are the first and the fourth terms.

Thus, the extremes of the proportion [tex]\(\frac{3}{4} = \frac{6}{8}\)[/tex] are:

[tex]\[ 3 \text{ and } 8 \][/tex]

Therefore, the correct option is:

D. 3 and 8