Get the information you need quickly and easily with IDNLearn.com. Ask your questions and receive comprehensive, trustworthy responses from our dedicated team of experts.

What is the mean of the distribution?

\begin{tabular}{|l|c|c|c|c|c|}
\hline
[tex]$x$[/tex] & 8 & 12 & 14 & 17 & 5 \\
\hline
[tex]$P(x)$[/tex] & [tex]$20\%$[/tex] & [tex]$30\%$[/tex] & [tex]$20\%$[/tex] & [tex]$8\%$[/tex] & [tex]$22\%$[/tex] \\
\hline
\end{tabular}

Select one:
A. 11.2
B. 10.46
C. 0.0002
D. 11.02


Sagot :

To find the mean of a probability distribution, we use the formula for the expected value:

[tex]\[ \mu = \sum (x \cdot P(x)) \][/tex]

where [tex]\( x \)[/tex] represents each value of the random variable, and [tex]\( P(x) \)[/tex] represents the corresponding probability.

Given the values and their probabilities from the distribution table:

[tex]\[ \begin{array}{|c|c|c|c|c|c|} \hline x & 8 & 12 & 14 & 17 & 5 \\ \hline P(x) & 0.20 & 0.30 & 0.20 & 0.08 & 0.22 \\ \hline \end{array} \][/tex]

we calculate the mean as follows:

1. Multiply each value by its probability:
- [tex]\( 8 \times 0.20 = 1.60 \)[/tex]
- [tex]\( 12 \times 0.30 = 3.60 \)[/tex]
- [tex]\( 14 \times 0.20 = 2.80 \)[/tex]
- [tex]\( 17 \times 0.08 = 1.36 \)[/tex]
- [tex]\( 5 \times 0.22 = 1.10 \)[/tex]

2. Sum these products:
[tex]\[ 1.60 + 3.60 + 2.80 + 1.36 + 1.10 = 10.46 \][/tex]

Therefore, the mean of the distribution is:

[tex]\[ \mu = 10.46 \][/tex]

The correct answer is:

[tex]\[\text{10.46}\][/tex]