Connect with knowledgeable experts and enthusiasts on IDNLearn.com. Discover prompt and accurate responses from our experts, ensuring you get the information you need quickly.
Sagot :
To simplify the expression [tex]\(\sqrt{39 y^9}\)[/tex] and remove all perfect squares from inside the square root, follow these steps:
1. Express the radicand (the expression inside the square root) as a product of perfect squares and any remaining factors:
[tex]\[ \sqrt{39 y^9} \][/tex]
2. Separate the expression into two parts: one part that contains the perfect squares and the other that does not:
Since [tex]\(y^9\)[/tex] can be written as [tex]\((y^4)^2 \cdot y\)[/tex], we separate the perfect square part:
[tex]\[ \sqrt{39 \cdot (y^4)^2 \cdot y} \][/tex]
3. Apply the property of square roots that states [tex]\(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\)[/tex]:
[tex]\[ \sqrt{39 \cdot (y^4)^2 \cdot y} = \sqrt{39} \cdot \sqrt{(y^4)^2} \cdot \sqrt{y} \][/tex]
4. Simplify the square root of the perfect square:
Since [tex]\(\sqrt{(y^4)^2} = y^4\)[/tex], we get:
[tex]\[ \sqrt{39} \cdot y^4 \cdot \sqrt{y} \][/tex]
5. Combine the simplified parts:
[tex]\[ \sqrt{39} \cdot y^4 \cdot \sqrt{y} = \sqrt{39} \cdot y^4 \cdot y^{1/2} \][/tex]
6. Combine the exponents of [tex]\(y\)[/tex]:
Using the property [tex]\(y^a \cdot y^b = y^{a+b}\)[/tex], we add the exponents [tex]\(4\)[/tex] and [tex]\(\frac{1}{2}\)[/tex]:
[tex]\[ y^4 \cdot y^{1/2} = y^{4 + \frac{1}{2}} = y^{\frac{8}{2} + \frac{1}{2}} = y^{\frac{9}{2}} \][/tex]
7. Write the final simplified form:
[tex]\[ \sqrt{39} \cdot y^{\frac{9}{2}} \][/tex]
Therefore, the simplified expression is:
[tex]\[ \sqrt{39 y^9} = \sqrt{39} \cdot y^{\frac{9}{2}} \][/tex]
1. Express the radicand (the expression inside the square root) as a product of perfect squares and any remaining factors:
[tex]\[ \sqrt{39 y^9} \][/tex]
2. Separate the expression into two parts: one part that contains the perfect squares and the other that does not:
Since [tex]\(y^9\)[/tex] can be written as [tex]\((y^4)^2 \cdot y\)[/tex], we separate the perfect square part:
[tex]\[ \sqrt{39 \cdot (y^4)^2 \cdot y} \][/tex]
3. Apply the property of square roots that states [tex]\(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\)[/tex]:
[tex]\[ \sqrt{39 \cdot (y^4)^2 \cdot y} = \sqrt{39} \cdot \sqrt{(y^4)^2} \cdot \sqrt{y} \][/tex]
4. Simplify the square root of the perfect square:
Since [tex]\(\sqrt{(y^4)^2} = y^4\)[/tex], we get:
[tex]\[ \sqrt{39} \cdot y^4 \cdot \sqrt{y} \][/tex]
5. Combine the simplified parts:
[tex]\[ \sqrt{39} \cdot y^4 \cdot \sqrt{y} = \sqrt{39} \cdot y^4 \cdot y^{1/2} \][/tex]
6. Combine the exponents of [tex]\(y\)[/tex]:
Using the property [tex]\(y^a \cdot y^b = y^{a+b}\)[/tex], we add the exponents [tex]\(4\)[/tex] and [tex]\(\frac{1}{2}\)[/tex]:
[tex]\[ y^4 \cdot y^{1/2} = y^{4 + \frac{1}{2}} = y^{\frac{8}{2} + \frac{1}{2}} = y^{\frac{9}{2}} \][/tex]
7. Write the final simplified form:
[tex]\[ \sqrt{39} \cdot y^{\frac{9}{2}} \][/tex]
Therefore, the simplified expression is:
[tex]\[ \sqrt{39 y^9} = \sqrt{39} \cdot y^{\frac{9}{2}} \][/tex]
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.