Get detailed and accurate responses to your questions with IDNLearn.com. Discover reliable and timely information on any topic from our network of knowledgeable professionals.

Simplify.
Remove all perfect squares from inside the square root. Assume [tex]$y$[/tex] is positive.

[tex]\sqrt{39 y^9} = [/tex]

[tex]\boxed{}[/tex]


Sagot :

To simplify the expression [tex]\(\sqrt{39 y^9}\)[/tex] and remove all perfect squares from inside the square root, follow these steps:

1. Express the radicand (the expression inside the square root) as a product of perfect squares and any remaining factors:
[tex]\[ \sqrt{39 y^9} \][/tex]

2. Separate the expression into two parts: one part that contains the perfect squares and the other that does not:
Since [tex]\(y^9\)[/tex] can be written as [tex]\((y^4)^2 \cdot y\)[/tex], we separate the perfect square part:
[tex]\[ \sqrt{39 \cdot (y^4)^2 \cdot y} \][/tex]

3. Apply the property of square roots that states [tex]\(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\)[/tex]:
[tex]\[ \sqrt{39 \cdot (y^4)^2 \cdot y} = \sqrt{39} \cdot \sqrt{(y^4)^2} \cdot \sqrt{y} \][/tex]

4. Simplify the square root of the perfect square:
Since [tex]\(\sqrt{(y^4)^2} = y^4\)[/tex], we get:
[tex]\[ \sqrt{39} \cdot y^4 \cdot \sqrt{y} \][/tex]

5. Combine the simplified parts:
[tex]\[ \sqrt{39} \cdot y^4 \cdot \sqrt{y} = \sqrt{39} \cdot y^4 \cdot y^{1/2} \][/tex]

6. Combine the exponents of [tex]\(y\)[/tex]:
Using the property [tex]\(y^a \cdot y^b = y^{a+b}\)[/tex], we add the exponents [tex]\(4\)[/tex] and [tex]\(\frac{1}{2}\)[/tex]:
[tex]\[ y^4 \cdot y^{1/2} = y^{4 + \frac{1}{2}} = y^{\frac{8}{2} + \frac{1}{2}} = y^{\frac{9}{2}} \][/tex]

7. Write the final simplified form:
[tex]\[ \sqrt{39} \cdot y^{\frac{9}{2}} \][/tex]

Therefore, the simplified expression is:
[tex]\[ \sqrt{39 y^9} = \sqrt{39} \cdot y^{\frac{9}{2}} \][/tex]