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Determine the domain of [tex]$y=\sqrt{x-5}-1$[/tex].

Sagot :

To determine the domain of the function [tex]\( y = \sqrt{x - 5} - 1 \)[/tex], we have to identify all the possible values of [tex]\( x \)[/tex] for which the expression is defined.

The primary concern here is the square root function [tex]\( \sqrt{x - 5} \)[/tex]. The square root function is only defined for non-negative values; that is, the expression inside the square root must be greater than or equal to zero.

Let's set up the inequality:

[tex]\[ x - 5 \geq 0 \][/tex]

To find the valid values of [tex]\( x \)[/tex], solve this inequality:

[tex]\[ x \geq 5 \][/tex]

This tells us that [tex]\( x \)[/tex] must be greater than or equal to 5 for the function [tex]\( \sqrt{x - 5} - 1 \)[/tex] to be defined. Therefore, for all [tex]\( x \geq 5 \)[/tex], the value inside the square root is non-negative, and the function will be defined.

Hence, the domain of the function [tex]\( y = \sqrt{x - 5} - 1 \)[/tex] is:

[tex]\[ [5, \infty) \][/tex]

This means that all real numbers [tex]\( x \)[/tex] starting from 5 and onwards (including 5) are in the domain of the function [tex]\( y = \sqrt{x - 5} - 1 \)[/tex].
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