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The table shows the results from a survey of 335 randomly selected households with pets. This survey was conducted by a new pet store that is opening nearby.

\begin{tabular}{|l|l|l|l|}
\hline & Have Children & Do Not Have Children & Total \\
\hline 1 pet & 38 & 53 & 91 \\
\hline 2 pets & 85 & 41 & 126 \\
\hline 3 or more pets & 46 & 72 & 118 \\
\hline Total & 169 & 166 & 335 \\
\hline
\end{tabular}

The pet store uses the data to make decisions about inventory. Complete the given statement.

A customer is more likely to have 1 pet and no children than they are to have [tex]$\square$[/tex].

Sagot :

GinnyAnsweridn
Let's analyze the probabilities given different events described in the table.

1. Probability of a household having 1 pet and no children:
The probability is [tex]\(0.1582089552238806\)[/tex] or approximately [tex]\(15.82\%\)[/tex].

2. Probability of a household having 1 pet and children:
The probability is [tex]\(0.11343283582089553\)[/tex] or approximately [tex]\(11.34\%\)[/tex].

3. Probability of a household having 2 pets and children:
The probability is [tex]\(0.2537313432835821\)[/tex] or approximately [tex]\(25.37\%\)[/tex].

4. Probability of a household having 3 or more pets and children:
The probability is [tex]\(0.1373134328358209\)[/tex] or approximately [tex]\(13.73\%\)[/tex].

5. Probability of a household having 2 pets and no children:
The probability is [tex]\(0.12238805970149254\)[/tex] or approximately [tex]\(12.24\%\)[/tex].

6. Probability of a household having 3 or more pets and no children:
The probability is [tex]\(0.21492537313432836\)[/tex] or approximately [tex]\(21.49\%\)[/tex].

From these probabilities, we can compare the probability of having 1 pet and no children to the other given scenarios:

- It's less likely than [tex]\(25.37\%\)[/tex] (2 pets with children).
- It's moderately likely compared to [tex]\(21.49\%\)[/tex] (3 or more pets with no children).
- It's more likely than [tex]\(11.34\%\)[/tex] (1 pet with children), [tex]\(13.73\%\)[/tex] (3 or more pets with children), and [tex]\(12.24\%\)[/tex] (2 pets with no children).

Hence, the correct statement to complete is:
A customer is more likely to have 1 pet and no children than they are to have 1 pet and children, 2 pets and no children, and 3 or more pets and children.

Based on this, we should select:
A customer is more likely to have 1 pet and no children than they are to have 2 pets and no children.
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