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Simplify the expression:
[tex]\[ (4xy + 2x)^2 \][/tex]


Sagot :

Sure, let's solve the problem of expanding the expression [tex]\((4xy + 2x)^2\)[/tex] step by step.

To expand [tex]\((4xy + 2x)^2\)[/tex], we can use the binomial theorem which states that [tex]\((a + b)^2 = a^2 + 2ab + b^2\)[/tex].

In the expression [tex]\((4xy + 2x)^2\)[/tex], we identify [tex]\(a = 4xy\)[/tex] and [tex]\(b = 2x\)[/tex]. Applying the binomial expansion formula, we get:

[tex]\[ (4xy + 2x)^2 = (4xy)^2 + 2 \cdot (4xy) \cdot (2x) + (2x)^2 \][/tex]

Now, let's compute each term individually:

1. Calculate [tex]\((4xy)^2\)[/tex]:
[tex]\[ (4xy)^2 = (4xy) \cdot (4xy) = 16x^2y^2 \][/tex]

2. Calculate [tex]\(2 \cdot (4xy) \cdot (2x)\)[/tex]:
[tex]\[ 2 \times (4xy) \times (2x) = 2 \times 4 \times 2 \times x \times y \times x = 16x^2y \][/tex]

3. Calculate [tex]\((2x)^2\)[/tex]:
[tex]\[ (2x)^2 = (2x) \cdot (2x) = 4x^2 \][/tex]

Now, we combine all the terms together:
[tex]\[ (4xy + 2x)^2 = 16x^2y^2 + 16x^2y + 4x^2 \][/tex]

Thus, the expanded form of [tex]\((4xy + 2x)^2\)[/tex] is:
[tex]\[ 16x^2y^2 + 16x^2y + 4x^2 \][/tex]

This is the detailed step-by-step expansion of the given expression.