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Sagot :
To evaluate [tex]\( f(3) \)[/tex] given the function [tex]\( f(x) = \frac{12x^2 - 3x + 20}{3} \)[/tex], follow these steps:
1. Substitute [tex]\( x = 3 \)[/tex] into the function:
[tex]\[ f(3) = \frac{12(3)^2 - 3(3) + 20}{3} \][/tex]
2. Calculate the expression in the numerator:
- Compute [tex]\( 3^2 \)[/tex]:
[tex]\[ 3^2 = 9 \][/tex]
- Multiply by 12:
[tex]\[ 12 \times 9 = 108 \][/tex]
- Multiply [tex]\( -3 \)[/tex] by 3:
[tex]\[ -3 \times 3 = -9 \][/tex]
- Add the constant term 20:
[tex]\[ 108 - 9 + 20 = 119 \][/tex]
Therefore, the numerator is 119.
3. Divide the numerator by 3:
[tex]\[ f(3) = \frac{119}{3} \][/tex]
4. Simplify the fraction:
The simplified fraction is:
[tex]\[ f(3) = 39.666666666666664 \][/tex]
So, the value of [tex]\( f(3) \)[/tex] is [tex]\( 39.666666666666664 \)[/tex].
1. Substitute [tex]\( x = 3 \)[/tex] into the function:
[tex]\[ f(3) = \frac{12(3)^2 - 3(3) + 20}{3} \][/tex]
2. Calculate the expression in the numerator:
- Compute [tex]\( 3^2 \)[/tex]:
[tex]\[ 3^2 = 9 \][/tex]
- Multiply by 12:
[tex]\[ 12 \times 9 = 108 \][/tex]
- Multiply [tex]\( -3 \)[/tex] by 3:
[tex]\[ -3 \times 3 = -9 \][/tex]
- Add the constant term 20:
[tex]\[ 108 - 9 + 20 = 119 \][/tex]
Therefore, the numerator is 119.
3. Divide the numerator by 3:
[tex]\[ f(3) = \frac{119}{3} \][/tex]
4. Simplify the fraction:
The simplified fraction is:
[tex]\[ f(3) = 39.666666666666664 \][/tex]
So, the value of [tex]\( f(3) \)[/tex] is [tex]\( 39.666666666666664 \)[/tex].
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