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Sagot :
Certainly! Let's break down the problem step-by-step:
1. We start with the expression [tex]\( 3k \)[/tex] which represents the total number of cookies. For this problem, we are considering that [tex]\( k \)[/tex] is 5. Therefore, the total number of cookies is:
[tex]\[ 3k = 3 \times 5 = 15 \][/tex]
2. Now, we need to divide these 15 cookies equally among 5 friends. We'll use integer division to determine how many cookies each friend will get.
3. Perform the division of the total number of cookies by the number of friends:
[tex]\[ \frac{15}{5} = 3 \][/tex]
This tells us that each friend gets 3 cookies.
4. Next, we need to see if there are any cookies left after distributing 3 cookies to each of the 5 friends. To find the remainder, we use the modulus operation:
[tex]\[ 15 \mod 5 = 0 \][/tex]
This indicates that there are no cookies left after the division.
So, to summarize:
- Each of the 5 friends gets 3 cookies.
- There are 0 cookies left.
Therefore, the result for the question is:
- Each friend gets 3 cookies.
- There are 0 cookies left.
1. We start with the expression [tex]\( 3k \)[/tex] which represents the total number of cookies. For this problem, we are considering that [tex]\( k \)[/tex] is 5. Therefore, the total number of cookies is:
[tex]\[ 3k = 3 \times 5 = 15 \][/tex]
2. Now, we need to divide these 15 cookies equally among 5 friends. We'll use integer division to determine how many cookies each friend will get.
3. Perform the division of the total number of cookies by the number of friends:
[tex]\[ \frac{15}{5} = 3 \][/tex]
This tells us that each friend gets 3 cookies.
4. Next, we need to see if there are any cookies left after distributing 3 cookies to each of the 5 friends. To find the remainder, we use the modulus operation:
[tex]\[ 15 \mod 5 = 0 \][/tex]
This indicates that there are no cookies left after the division.
So, to summarize:
- Each of the 5 friends gets 3 cookies.
- There are 0 cookies left.
Therefore, the result for the question is:
- Each friend gets 3 cookies.
- There are 0 cookies left.
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