Discover how IDNLearn.com can help you find the answers you need quickly and easily. Join our community to access reliable and comprehensive responses to your questions from experienced professionals.
Sagot :
To find the absolute minimum and maximum values of the function [tex]\( f(x) = x^4 - 18x^2 + 9 \)[/tex] on the interval [tex]\([-2, 7]\)[/tex], follow these steps:
1. Define the function:
[tex]\[ f(x) = x^4 - 18x^2 + 9 \][/tex]
2. Find the critical points of the function:
- To find the critical points, we first need to calculate the derivative of the function:
[tex]\[ f'(x) = \frac{d}{dx}(x^4 - 18x^2 + 9) = 4x^3 - 36x \][/tex]
- Set the derivative equal to zero to find the critical points:
[tex]\[ 4x^3 - 36x = 0 \][/tex]
Factor out the common term:
[tex]\[ 4x(x^2 - 9) = 0 \][/tex]
Which simplifies to:
[tex]\[ 4x(x - 3)(x + 3) = 0 \][/tex]
This gives us the critical points [tex]\( x = 0, x = 3, x = -3 \)[/tex].
3. Evaluate the function at the critical points and the boundary points:
- The boundary points are [tex]\( x = -2 \)[/tex] and [tex]\( x = 7 \)[/tex].
- Calculate [tex]\( f(x) \)[/tex] at these points:
[tex]\[ f(-2) = (-2)^4 - 18(-2)^2 + 9 = 16 - 72 + 9 = -47 \][/tex]
[tex]\[ f(7) = 7^4 - 18(7^2) + 9 = 2401 - 882 + 9 = 1528 \][/tex]
- Calculate [tex]\( f(x) \)[/tex] at the critical points within the interval [tex]\([-2, 7]\)[/tex]:
- For [tex]\( x = 0 \)[/tex]:
[tex]\[ f(0) = 0^4 - 18(0^2) + 9 = 9 \][/tex]
- For [tex]\( x = 3 \)[/tex]:
[tex]\[ f(3) = 3^4 - 18(3^2) + 9 = 81 - 162 + 9 = -72 \][/tex]
- [tex]\( x = -3 \)[/tex] is not within the interval [tex]\([-2, 7]\)[/tex], so we do not consider it.
4. Determine the absolute minimum and maximum values:
- We must compare the function values at the critical points and boundaries:
[tex]\[ f(-2) = -47 \][/tex]
[tex]\[ f(7) = 1528 \][/tex]
[tex]\[ f(0) = 9 \][/tex]
[tex]\[ f(3) = -72 \][/tex]
- From these calculations, we observe:
- The absolute minimum value is [tex]\( -72 \)[/tex] at [tex]\( x = 3 \)[/tex].
- The absolute maximum value is [tex]\( 1528 \)[/tex] at [tex]\( x = 7 \)[/tex].
Therefore, the absolute minimum value of [tex]\( f(x) \)[/tex] on the interval [tex]\([-2, 7]\)[/tex] is [tex]\(-72\)[/tex] and the absolute maximum value is [tex]\( 1528 \)[/tex].
1. Define the function:
[tex]\[ f(x) = x^4 - 18x^2 + 9 \][/tex]
2. Find the critical points of the function:
- To find the critical points, we first need to calculate the derivative of the function:
[tex]\[ f'(x) = \frac{d}{dx}(x^4 - 18x^2 + 9) = 4x^3 - 36x \][/tex]
- Set the derivative equal to zero to find the critical points:
[tex]\[ 4x^3 - 36x = 0 \][/tex]
Factor out the common term:
[tex]\[ 4x(x^2 - 9) = 0 \][/tex]
Which simplifies to:
[tex]\[ 4x(x - 3)(x + 3) = 0 \][/tex]
This gives us the critical points [tex]\( x = 0, x = 3, x = -3 \)[/tex].
3. Evaluate the function at the critical points and the boundary points:
- The boundary points are [tex]\( x = -2 \)[/tex] and [tex]\( x = 7 \)[/tex].
- Calculate [tex]\( f(x) \)[/tex] at these points:
[tex]\[ f(-2) = (-2)^4 - 18(-2)^2 + 9 = 16 - 72 + 9 = -47 \][/tex]
[tex]\[ f(7) = 7^4 - 18(7^2) + 9 = 2401 - 882 + 9 = 1528 \][/tex]
- Calculate [tex]\( f(x) \)[/tex] at the critical points within the interval [tex]\([-2, 7]\)[/tex]:
- For [tex]\( x = 0 \)[/tex]:
[tex]\[ f(0) = 0^4 - 18(0^2) + 9 = 9 \][/tex]
- For [tex]\( x = 3 \)[/tex]:
[tex]\[ f(3) = 3^4 - 18(3^2) + 9 = 81 - 162 + 9 = -72 \][/tex]
- [tex]\( x = -3 \)[/tex] is not within the interval [tex]\([-2, 7]\)[/tex], so we do not consider it.
4. Determine the absolute minimum and maximum values:
- We must compare the function values at the critical points and boundaries:
[tex]\[ f(-2) = -47 \][/tex]
[tex]\[ f(7) = 1528 \][/tex]
[tex]\[ f(0) = 9 \][/tex]
[tex]\[ f(3) = -72 \][/tex]
- From these calculations, we observe:
- The absolute minimum value is [tex]\( -72 \)[/tex] at [tex]\( x = 3 \)[/tex].
- The absolute maximum value is [tex]\( 1528 \)[/tex] at [tex]\( x = 7 \)[/tex].
Therefore, the absolute minimum value of [tex]\( f(x) \)[/tex] on the interval [tex]\([-2, 7]\)[/tex] is [tex]\(-72\)[/tex] and the absolute maximum value is [tex]\( 1528 \)[/tex].
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.