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Part A

A proton in a linear accelerator has a de Broglie wavelength of 129 pm. What is the speed of the proton?

Express your answer with the appropriate units.

[tex] \text{Speed} = 3.07 \times 10^3 \, \text{m/s} \]

Sagot :

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Final answer:

To find the speed of a proton given its de Broglie wavelength of 129 pm, you can use the de Broglie wavelength formula and the momentum-speed relationship.


Explanation:

The de Broglie wavelength formula is λ = h / p, where λ is the wavelength, h is Planck's constant, and p is the momentum of the particle. Given that the de Broglie wavelength of a proton in a linear accelerator is 129 pm, we can find the speed of the proton by using the formula v = p / m, where v is the speed, p is the momentum, and m is the mass of the proton.


Learn more about de Broglie wavelength and speed of particles here:

https://brainly.com/question/46828968


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