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Use the compound interest formulas, [tex]A = P\left(1+\frac{r}{n}\right)^{nt}[/tex] and [tex]A = Pe^{rt}[/tex], to solve the following problem.

Find the accumulated value of an investment of [tex]$\$10,000[/tex] for 3 years at an interest rate of [tex]6.5\%[/tex] if the money is:

a. compounded semiannually
b. compounded monthly
c. compounded continuously

a. What is the accumulated value if the money is compounded semiannually?
[tex]\$\ \square[/tex] (Round your answer to the nearest cent.)


Sagot :

To determine the accumulated value (A) of an investment using the compound interest formula, we need to use the formula:

[tex]\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \][/tex]

where:
- [tex]\( P \)[/tex] is the principal amount (initial investment),
- [tex]\( r \)[/tex] is the annual interest rate (in decimal form),
- [tex]\( n \)[/tex] is the number of times the interest is compounded per year,
- [tex]\( t \)[/tex] is the time the money is invested for, in years.

Given:
- [tex]\( P = \$10,000 \)[/tex]
- [tex]\( r = 6.5\% = 0.065 \)[/tex]
- [tex]\( n \)[/tex] = 2 (since the interest is compounded semiannually)
- [tex]\( t = 3 \)[/tex] years

Now we plug these values into the formula:

[tex]\[ A = 10000 \left(1 + \frac{0.065}{2}\right)^{2 \cdot 3} \][/tex]

First, calculate the interest rate per compounding period:

[tex]\[ \frac{0.065}{2} = 0.0325 \][/tex]

Then add 1 to this value:

[tex]\[ 1 + 0.0325 = 1.0325 \][/tex]

Raise this to the power of the total number of compounding periods:

[tex]\[ 1.0325^{6} \][/tex]

Now, multiplying by the principal amount:

[tex]\[ A = 10000 \times (1.0325^6) \][/tex]

Through detailed calculations, the accumulated value (rounded to the nearest cent) after 3 years with semiannual compounding is:

[tex]\[ \boxed{12115.47} \][/tex]

So, the accumulated value, if the money is compounded semiannually, is $12,115.47.