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Rewrite the function by completing the square.

[tex]\[
\begin{array}{l}
f(x) = x^2 - 9x + 14 \\
f(x) = \square(x + \square)^2 + \square
\end{array}
\][/tex]


Sagot :

To rewrite the function [tex]\( f(x) = x^2 - 9x + 14 \)[/tex] by completing the square, we will follow these steps:

1. Start with the original quadratic function:
[tex]\[ f(x) = x^2 - 9x + 14 \][/tex]

2. Identify the coefficients [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex] from the quadratic expression [tex]\( ax^2 + bx + c \)[/tex]:
[tex]\[ a = 1, \quad b = -9, \quad c = 14 \][/tex]

3. Complete the square:
- Take half of the coefficient of [tex]\( x \)[/tex], which is [tex]\( b \)[/tex]. In this case, half of [tex]\( -9 \)[/tex] is [tex]\( -4.5 \)[/tex]:
[tex]\[ \frac{b}{2} = -\frac{9}{2} = -4.5 \][/tex]

- Square this value:
[tex]\[ \left(-\frac{9}{2}\right)^2 = \left(-4.5\right)^2 = 20.25 \][/tex]

- Rewrite the original function as the square of a binomial and adjust the constant term:
[tex]\[ f(x) = x^2 - 9x + 14 \][/tex]
[tex]\[ f(x) = \left(x - 4.5\right)^2 - 20.25 + 14 \][/tex]

- Combine the constant terms:
[tex]\[ f(x) = \left(x - 4.5\right)^2 - 6.25 \][/tex]

4. Write the completed square form:
[tex]\[ f(x) = \left(x - 4.5\right)^2 - 6.25 \][/tex]

Thus, by completing the square, the function [tex]\( f(x) = x^2 - 9x + 14 \)[/tex] can be rewritten as:
[tex]\[ f(x) = \left( x - 4.5 \right)^2 - 6.25 \][/tex]

In the form given in the problem:
[tex]\[ f(x) = \boxed{1}(x + \boxed{4.5})^2 + \boxed{-6.25} \][/tex]
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