Discover a wealth of information and get your questions answered on IDNLearn.com. Whether it's a simple query or a complex problem, our community has the answers you need.
Sagot :
To determine which of the provided probability distributions is valid, we must check each distribution against the criteria for being a valid probability distribution:
1. Each probability value must be between 0 and 1 (inclusive).
2. The sum of the probabilities must be exactly 1.
### Probability Distribution A
[tex]\[ \begin{array}{|c|c|} \hline \multicolumn{2}{|c|}{ Probability Distribution A } \\ \hline X & P(x) \\ \hline 1 & -0.14 \\ \hline 2 & 0.6 \\ \hline 3 & 0.25 \\ \hline 4 & 0.29 \\ \hline \end{array} \][/tex]
1. Check the range of each probability:
- [tex]\( -0.14 \)[/tex] is not between 0 and 1, so it fails the first criterion.
Therefore, Probability Distribution A is not valid.
### Probability Distribution B
[tex]\[ \begin{array}{|c|c|} \hline \multicolumn{2}{|c|}{ Probability Distribution B } \\ \hline X & P(x) \\ \hline 1 & 0 \\ \hline 2 & 0.45 \\ \hline 3 & 0.16 \\ \hline 4 & 0.39 \\ \hline \end{array} \][/tex]
1. Check the range of each probability:
- [tex]\( 0 \)[/tex] is between 0 and 1.
- [tex]\( 0.45 \)[/tex] is between 0 and 1.
- [tex]\( 0.16 \)[/tex] is between 0 and 1.
- [tex]\( 0.39 \)[/tex] is between 0 and 1.
2. Sum the probabilities:
[tex]\[ 0 + 0.45 + 0.16 + 0.39 = 1 \][/tex]
Since all probabilities are within the required range and their sum is 1, Probability Distribution B is valid.
### Probability Distribution C
[tex]\[ \begin{array}{|c|c|} \hline \multicolumn{2}{|c|}{ Probability Distribution C } \\ \hline X & P(x) \\ \hline 1 & 0.45 \\ \hline 2 & 1.23 \\ \hline 3 & -0.87 \\ \hline \end{array} \][/tex]
1. Check the range of each probability:
- [tex]\( 0.45 \)[/tex] is between 0 and 1.
- [tex]\( 1.23 \)[/tex] is not between 0 and 1.
- [tex]\( -0.87 \)[/tex] is not between 0 and 1.
Since some probabilities are not within the required range, Probability Distribution C is not valid.
### Conclusion
Only Probability Distribution B represents a valid probability distribution.
1. Each probability value must be between 0 and 1 (inclusive).
2. The sum of the probabilities must be exactly 1.
### Probability Distribution A
[tex]\[ \begin{array}{|c|c|} \hline \multicolumn{2}{|c|}{ Probability Distribution A } \\ \hline X & P(x) \\ \hline 1 & -0.14 \\ \hline 2 & 0.6 \\ \hline 3 & 0.25 \\ \hline 4 & 0.29 \\ \hline \end{array} \][/tex]
1. Check the range of each probability:
- [tex]\( -0.14 \)[/tex] is not between 0 and 1, so it fails the first criterion.
Therefore, Probability Distribution A is not valid.
### Probability Distribution B
[tex]\[ \begin{array}{|c|c|} \hline \multicolumn{2}{|c|}{ Probability Distribution B } \\ \hline X & P(x) \\ \hline 1 & 0 \\ \hline 2 & 0.45 \\ \hline 3 & 0.16 \\ \hline 4 & 0.39 \\ \hline \end{array} \][/tex]
1. Check the range of each probability:
- [tex]\( 0 \)[/tex] is between 0 and 1.
- [tex]\( 0.45 \)[/tex] is between 0 and 1.
- [tex]\( 0.16 \)[/tex] is between 0 and 1.
- [tex]\( 0.39 \)[/tex] is between 0 and 1.
2. Sum the probabilities:
[tex]\[ 0 + 0.45 + 0.16 + 0.39 = 1 \][/tex]
Since all probabilities are within the required range and their sum is 1, Probability Distribution B is valid.
### Probability Distribution C
[tex]\[ \begin{array}{|c|c|} \hline \multicolumn{2}{|c|}{ Probability Distribution C } \\ \hline X & P(x) \\ \hline 1 & 0.45 \\ \hline 2 & 1.23 \\ \hline 3 & -0.87 \\ \hline \end{array} \][/tex]
1. Check the range of each probability:
- [tex]\( 0.45 \)[/tex] is between 0 and 1.
- [tex]\( 1.23 \)[/tex] is not between 0 and 1.
- [tex]\( -0.87 \)[/tex] is not between 0 and 1.
Since some probabilities are not within the required range, Probability Distribution C is not valid.
### Conclusion
Only Probability Distribution B represents a valid probability distribution.
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.