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### (a) Completing the frequency distribution
#### Given Data
The doctors the patients went to see:
[tex]\[ W, F, M, W, P, F, M, F, P, W, F, M, F, W, P, T, T, P, T, M, W, M, F, W \][/tex]
#### Frequency Distribution Table
To find the frequencies, count how many times each doctor appears in the data set:
- Dr. Foster (F): Count the occurrences of 'F'.
- F appears 6 times.
- Dr. Mitchell (M): Count the occurrences of 'M'.
- M appears 5 times.
- Dr. Phillips (P): Count the occurrences of 'P'.
- P appears 4 times.
- Dr. Tran (T): Count the occurrences of 'T'.
- T appears 3 times.
- Dr. Washington (W): Count the occurrences of 'W'.
- W appears 6 times.
After counting, we get the following frequency distribution:
[tex]\[ \begin{tabular}{cc} Doctor & Frequency \\ \hline F & 6 \\ M & 5 \\ P & 4 \\ T & 3 \\ W & 6 \\ \end{tabular} \][/tex]
### (b) Patients who saw a doctor affiliated with City Med
#### City Med Affiliation
According to the given medical group affiliations:
- City Med: Dr. Foster (F) and Dr. Tran (T).
To find out how many patients saw a City Med-affiliated doctor, sum the frequencies of Dr. Foster (F) and Dr. Tran (T):
- Frequency of Dr. Foster (F) is 6.
- Frequency of Dr. Tran (T) is 3.
Adding these frequencies together:
[tex]\[ 6 + 3 = 9 \][/tex]
Thus, the number of patients who went to see a doctor affiliated with the City Med medical group is:
[tex]\[ 9 \text{ patients} \][/tex]
So, summarizing the solution:
### (a) Frequency Distribution
[tex]\[ \begin{tabular}{cc} Doctor & Frequency \\ \hline F & 6 \\ M & 5 \\ P & 4 \\ T & 3 \\ W & 6 \\ \end{tabular} \][/tex]
### (b) Number of Patients for City Med
[tex]\[ 9 \text{ patients} \][/tex]
### (a) Completing the frequency distribution
#### Given Data
The doctors the patients went to see:
[tex]\[ W, F, M, W, P, F, M, F, P, W, F, M, F, W, P, T, T, P, T, M, W, M, F, W \][/tex]
#### Frequency Distribution Table
To find the frequencies, count how many times each doctor appears in the data set:
- Dr. Foster (F): Count the occurrences of 'F'.
- F appears 6 times.
- Dr. Mitchell (M): Count the occurrences of 'M'.
- M appears 5 times.
- Dr. Phillips (P): Count the occurrences of 'P'.
- P appears 4 times.
- Dr. Tran (T): Count the occurrences of 'T'.
- T appears 3 times.
- Dr. Washington (W): Count the occurrences of 'W'.
- W appears 6 times.
After counting, we get the following frequency distribution:
[tex]\[ \begin{tabular}{cc} Doctor & Frequency \\ \hline F & 6 \\ M & 5 \\ P & 4 \\ T & 3 \\ W & 6 \\ \end{tabular} \][/tex]
### (b) Patients who saw a doctor affiliated with City Med
#### City Med Affiliation
According to the given medical group affiliations:
- City Med: Dr. Foster (F) and Dr. Tran (T).
To find out how many patients saw a City Med-affiliated doctor, sum the frequencies of Dr. Foster (F) and Dr. Tran (T):
- Frequency of Dr. Foster (F) is 6.
- Frequency of Dr. Tran (T) is 3.
Adding these frequencies together:
[tex]\[ 6 + 3 = 9 \][/tex]
Thus, the number of patients who went to see a doctor affiliated with the City Med medical group is:
[tex]\[ 9 \text{ patients} \][/tex]
So, summarizing the solution:
### (a) Frequency Distribution
[tex]\[ \begin{tabular}{cc} Doctor & Frequency \\ \hline F & 6 \\ M & 5 \\ P & 4 \\ T & 3 \\ W & 6 \\ \end{tabular} \][/tex]
### (b) Number of Patients for City Med
[tex]\[ 9 \text{ patients} \][/tex]
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